與條件

Question

總場我有如下表測試

id order hour 

我有兩種情況：

第一種情況：無關

id order hour 
1 1  20 
2 1  40 
3 1  50 

情況二：

id order hour 
1 1  20 
1 2  50 
1 3  70 
2 1  40 
2 2  10 
2 3  20 
2 4  90 
3 1  50 

我需要得到 ID小時

1 120 //hour total=50+70 for id=1 when order >1 
2 120//hour total for=10+20+90 id=2 when order >1 
3 50 // nothing to do because I have one row for id=3 

我怎麼能這樣做？

Answer 1

請嘗試以下操作。對於id = 3的SUM將是50，所以在這種情況下仍然可以使用SUM。

SELECT id, SUM(hour) AS HourTotal 
FROM YourTable t1 
WHERE [order] > 1 OR 
     NOT EXISTS (SELECT 1 FROM YourTable t2 WHERE t1.id = t2.id AND [order] > 1) 
GROUP BY id 

Answer 2

以下代碼正在工作。我測試過了。請嘗試

select ID,SUM(HourTotal) as hourtotal from (
    select id,HourTotal,row_num 
    from (SELECT id, hour_n AS HourTotal ,ROW_NUMBER() over(partition by id order by id) row_num 
    FROM id)a 
    where a.id!=a.row_num)b 
    group by id 

Answer 3

請嘗試以下code.it工作

select ID,SUM(HourTotal) as hourtotal from (
     select id,HourTotal,row_num 
     from (SELECT id, hour_n AS HourTotal ,ROW_NUMBER() over(partition by id order by id) row_num 
     FROM id)a 
     where a.id!=a.row_num)b 
     group by id