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我遇到了執行結果問題。如果你追蹤它，這似乎是正確的。 但是，它給出了錯誤的結果。 如果你輸入99和99這給了5318，但它應該給9801.通過在nasm中重複添加堆棧進行乘法運算
順便說一句，該程序通過將被乘數（第一輸入）接受兩個2位數字和乘法，直到它在乘數滿足值（第二個輸入）
我試圖找到問題，似乎當我使用字大小的分裂它給隨機值。字大小高達65,656，但結果超過255時會破壞。爲什麼？
請注意第一個選項是重複加法運算的乘法運算。
有一點幫助是非常感謝。如下圖所示
section .data
msg db "Menu: "
msgLen equ $ -msg
msg2 db "[1]Multiplication by repeated addition"
msgLen2 equ $ -msg2
msg3 db "[2]Division by repeated subtraction"
msgLen3 equ $ -msg3
msg4 db "[3]Exit"
msgLen4 equ $ -msg4
msg5 db "Enter two numbers: "
msgLen5 equ $ -msg5
line db "", 10
result dw 0
ten dw 10
quo1 dw 0
quo2 dw 0
quo3 dw 0
rem1 dw 0
rem2 dw 0
rem3 dw 0
temp1 db 0
temp2 db 0
temp3 db 0
section .bss
choice resb 1
num1a resw 1
num1b resw 1
num2a resw 1
num2b resw 1
section .text
global _start
_start:
do_while:
mov eax, 4
mov ebx, 1
mov ecx, msg
mov edx, msgLen
int 80h
mov eax, 4
mov ebx, 1
mov ecx, line
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, msg2
mov edx, msgLen2
int 80h
mov eax, 4
mov ebx, 1
mov ecx, line
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, msg3
mov edx, msgLen3
int 80h
mov eax, 4
mov ebx, 1
mov ecx, line
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, msg4
mov edx, msgLen4
int 80h
mov eax, 4
mov ebx, 1
mov ecx, line
mov edx, 1
int 80h
mov eax, 3
mov ebx, 0
mov ecx, choice
mov edx, 2
int 80h
sub byte [choice], 30h
cmp byte [choice], 1
je menu1
;cmp byte [choice], 2
;je menu2
cmp byte [choice], 3
je exit
jg do_while
jl do_while
menu1:
mov eax, 4
mov ebx, 1
mov ecx, msg5
mov edx, msgLen5
int 80h
mov eax, 3
mov ebx, 0
mov ecx, num1a
mov edx, 1
int 80h
mov eax, 3
mov ebx, 0
mov ecx, num1b
mov edx, 2
int 80h
mov eax, 3
mov ebx, 0
mov ecx, num2a
mov edx, 1
int 80h
mov eax, 3
mov ebx, 0
mov ecx, num2b
mov edx, 2
int 80h
sub word [num1a], 30h ;conversion
sub word [num1b], 30h
sub word [num2a], 30h
sub word [num2b], 30h
push result
push word [num1a]
push word [num1b]
push word [num2a]
push word [num2b]
call func1
mov ax, [result] ;9801
mov dx, 0
mov bx, 10
div bx
mov word [quo1], ax ;980
mov word [rem1], dx ;1
mov ax, [quo1]
mov dx, 0
mov bx, 10
div bx
mov word [quo2], ax ;98
mov word [rem2], dx ;0
mov ax, [quo2]
mov dx, 0
mov bx, 10
div bx
mov word [quo3], ax ;9
mov word [rem3], dx ;8
add word [quo3], 30h
add word [rem3], 30h
add word [rem2], 30h
add word [rem1], 30h
mov eax, 4
mov ebx, 1
mov ecx, quo3
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, rem3
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, rem2
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, rem1
mov edx, 1
int 80h
mov eax, 4
mov ebx, 1
mov ecx, line
mov edx, 1
int 80h
jmp do_while
func1:
mov ebp, esp
mov ax, [ebp+10] ;90
mov dx, 0
mul word [ten]
mov [ebp+10], ax
mov ax, [ebp+8] ;9
add word [ebp+10], ax ;99 on [ebp+10]
mov ax, [ebp+6] ;90
mov dx, 0
mul word [ten]
mov [ebp+6], ax
mov ax, [ebp+4] ;9
add word [ebp+6], ax ;99 on [ebp+6]
while1:
mov ax, [ebp+10]
add ax, [ebp+10]
dec word [ebp+6]
cmp word [ebp+6], 1
jne while1
end1:
mov ebx, [ebp+12]
mov [ebx], ax
ret 12
exit:
mov eax, 1
mov ebx, 0
int 80h
你確定'numXY'變量的高字節是0嗎？ – Michael
什麼numXY？對不起，你可以澄清。 – ThisGuy
XY = 1a，1b等 – Michael