調用同一類中的不同圖層

-1

我在這裏尋求一些幫助，我的代碼正面臨着一條死衚衕。我試圖使用Intent將screen1.java中的值傳遞給screen2.java。傳遞價值是好的，我設法通過它;然而，當我檢查使用if語句程序崩潰。下面是我的文件，plzzzzzzzzzzz幫助調用同一類中的不同圖層

screen1.java

package test.android; 
import android.app.Activity; 
import android.content.Intent; 
import android.os.Bundle; 
import android.view.View; 
import android.widget.Button; 

public class screen1 extends Activity 
{ 
    static String strKey = "Hello"; 
    static final String strValue = "Hello"; 

    public void onCreate(Bundle icicle) 
    { 
     super.onCreate(icicle); 
     setContentView(R.layout.screen1); 

     //** button A  
     Button A = (Button) findViewById(R.id.btnClickA); 
     A.setOnClickListener(new View.OnClickListener() { 
      public void onClick(View arg0) { 
       Intent i = new Intent(screen1.this, screen2.class); 
       strKey = "NAME"; 
       i.setClassName("packageName", "packageName.IntentClass"); 
       String term = "Hello"; 
       i.putExtra("packageName.term", term); 

       //i.putExtra(strKey, strValue); 
       startActivity(i); 
      } 
     }); 
     //** 
     //** button B  
     Button B = (Button) findViewById(R.id.btnClickB); 
     B.setOnClickListener(new View.OnClickListener() { 
      public void onClick(View arg0) { 
       Intent i = new Intent(screen1.this, screen3.class); 
       startActivity(i); 
      } 
     }); 
     //** 

    } 
}

screen2.java

package test.android; 
import android.app.Activity; 
import android.os.Bundle; 
import android.view.View; 
import android.widget.Button; 

public class screen2 extends Activity 
{ 
    public void onCreate(Bundle icicle) 
    { 
     Bundle extras = getIntent().getExtras(); 
     String term = extras.getString("packageName.term"); 

     System.out.println("--- Name is -->"+ term); 

     if(term.equalsIgnoreCase("Hello") || term.equalsIgnoreCase("Name")){ 
      super.onCreate(icicle); 
      setContentView(R.layout.screen3); 
      Button b = (Button) findViewById(R.id.btnClick3); 
      b.setOnClickListener(new View.OnClickListener() { 
       public void onClick(View arg0) { 
        setResult(RESULT_OK); 
        finish(); 
       } 
      }); 
     } else { 
      super.onCreate(icicle); 
      setContentView(R.layout.screen2); 
      Button b = (Button) findViewById(R.id.btnClick2); 
      b.setOnClickListener(new View.OnClickListener() { 
       public void onClick(View arg0) { 
        setResult(RESULT_OK); 
        finish(); 
       } 
      }); 
     } 
     // DOES NOT WORK !!!!!!!!! 
     System.out.println("--- Name is -->"+ term); 


    } 
}

佈局： screen1.xml

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    android:orientation="vertical" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
> 
<TextView 
    android:layout_width="fill_parent" 
    android:layout_height="wrap_content" 
    android:text="You are in the first Screen" 
/> 
<Button 
    android:id ="@+id/btnClickA" 
    android:background="@drawable/sleep0" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:text="Open Screen 2" 
/> 
<Button 
    android:id ="@+id/btnClickB" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:text="Open Screen 3" 
/> 
<ImageView android:id="@+id/icon" android:layout_width="wrap_content" 
android:layout_height="fill_parent" android:src="@drawable/icon" 
android:layout_gravity="center"/> 
</LinearLayout>

screen2.xml

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    android:orientation="vertical" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
> 
<TextView 
    android:layout_width="fill_parent" 
    android:layout_height="wrap_content" 
    android:text="You are in Screen 2" 
/> 
<Button 
    android:id ="@+id/btnClick2" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:text="Close" 
/> 
</LinearLayout>

screen3.xml

<?xml version="1.0" encoding="utf-8"?> 
<!-- ScrollView: will allow the layout to be scroll Up/Down and Left/right --> 
<ScrollView 
    android:id="@+id/widget54" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
    xmlns:android="http://schemas.android.com/apk/res/android" 
    > 
<LinearLayout 
    android:orientation="vertical" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
    android:scrollbars="vertical" 

> 
<TextView 
    android:layout_width="fill_parent" 
    android:layout_height="wrap_content" 
    android:text="You are in Screen 3" 
/> 
<Button 
    android:id ="@+id/btnClick3" 
    android:background="@drawable/sss" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:text="Close" 
/> 
<ImageView android:id="@+id/sssq" android:layout_width="fill_parent" 
android:layout_height="fill_parent" android:src="@drawable/sssq" 
android:layout_gravity="center" /> 

</LinearLayout> 
</ScrollView>

的AndroidManifest.xml

<manifest xmlns:android="http://schemas.android.com/apk/res/android" 
    package="test.android"> 
    <application android:icon="@drawable/icon"> 

     <activity android:name="screen1" 
         android:label="SCREEN 1"> 

     <intent-filter> 
     <action android:name="android.intent.action.MAIN" /> 
     <category android:name="android.intent.category.LAUNCHER" /> 
     </intent-filter> 

     </activity> 
     <activity android:name="screen2" 
         android:label="SCREEN 2"> 
     </activity> 

     <activity android:name="screen3" 
         android:label="SCREEN 3"> 
     </activity> 
    </application> 
</manifest>

===== 該錯誤是由這些行的代碼中引起screen2.java：

if(term.equalsIgnoreCase("Hello") || term.equalsIgnoreCase("Name")){ 
     super.onCreate(icicle); 
     setContentView(R.layout.screen3); 
     Button b = (Button) findViewById(R.id.btnClick3); 
     b.setOnClickListener(new View.OnClickListener() { 
     public void onClick(View arg0) { 
     setResult(RESULT_OK); 
     finish(); 
     } 
     }); 
    } 
    else { 
     super.onCreate(icicle); 
     setContentView(R.layout.screen2); 
     Button b = (Button) findViewById(R.id.btnClick2); 
     b.setOnClickListener(new View.OnClickListener() { 
      public void onClick(View arg0) { 
       setResult(RESULT_OK); 
       finish(); 
      } 
     }); 
    }

**注意，如果我擺脫了整個IF語句，並只與ELSE一起使用，程序工作正常。

來源

2010-05-20 khalid

如果將信息傳遞給Intent構造函數，則不需要i.setClassName（「packageName」，「packageName.IntentClass」）。順便說一句你的Screen3調用工作正常嗎？

來源

2010-05-20 03:59:56 Karan

所以你說我應該只是越過這條線「i.setClassName（」packageName「，」packageName.IntentClass「）」？是的，調用screen3可以正常工作;當我點擊主屏幕（screen1.java）中的按鈕B時，它將我發送到screen3。 – khalid 2010-05-20 04:41:07

非常感謝你，我只是評論說，線條和它的工作就像一個魅力。 – khalid 2010-05-20 04:55:45

你錯誤地傳遞數據，試試這個：

public void onClick(View arg0) { 
       Intent i = new Intent(screen1.this, screen2.class); 
       strKey = "NAME"; 
       //NO NEED FOR THIS, REMOVE -> i.setClassName("packageName", "packageName.IntentClass"); 
       String term = "Hello"; 
       //Add your string to a bundle: 
       Bundle b = new Bundle(); 
       b.putString("packageName.term", term); 
       //Then add the bundle to your intent 
       i.putExtra(b); 

       //i.putExtra(strKey, strValue); 
       startActivity(i); 
      }

你在屏幕2活動獲取它的方式是好的，我只是檢查，如果長期爲null：

if(term != null && (term.equalsIgnoreCase("Hello") || term.equalsIgnoreCase("Name"))){

。 ..

來源

2010-05-20 17:36:51

調用同一類中的不同圖層

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