我開發了一個Web服務,用於使用wcf post方法從移動應用程序中將數據存儲在數據庫中。以下是我用來將數據保存在數據庫中的方法。wcf的POST方法有時不會在服務器上發送數據?
public void AddBook3(string Ans3, string Ans4, string Ans5, string Ans6, string Ans7, string Ans8, string Ans9, string Ans10, string Ans11, string Ans12,string customername)
{
server = "localhost";
database = "Feed";
uid = "root";
string message;
// password = "password";
mySqlConnection = new MySql.Data.MySqlClient.MySqlConnection();
mySqlConnection.ConnectionString = "SERVER=" + server + ";" + "DATABASE=" +
database + ";" + "UID=" + uid + ";";
mySqlConnection.Open();
MySqlCommand cmd = new MySqlCommand("insert into answers(ans3,ans4,ans5,ans6,ans7,ans8,ans9,ans10,ans11,ans12,customername) values(@ans3,@ans4,@ans5,@ans6,@ans7,@ans8,@ans9,@ans10,@ans11,@ans12,@customername)", mySqlConnection);
cmd.Parameters.AddWithValue("@ans3", Ans3);
cmd.Parameters.AddWithValue("@ans4", Ans4);
cmd.Parameters.AddWithValue("@ans5", Ans5);
cmd.Parameters.AddWithValue("@ans6", Ans6);
cmd.Parameters.AddWithValue("@ans7", Ans7);
cmd.Parameters.AddWithValue("@ans8", Ans8);
cmd.Parameters.AddWithValue("@ans9", Ans9);
cmd.Parameters.AddWithValue("@ans10", Ans10);
cmd.Parameters.AddWithValue("@ans11", Ans11);
cmd.Parameters.AddWithValue("@ans12", Ans12);
cmd.Parameters.AddWithValue("@customername", customername);
int result = cmd.ExecuteNonQuery();
if (result == 1)
{
// message = userinfo.Id + "user info inserteddd";
}
else
{
// message = userinfo.Id + "information not insertedd";
}
}
以下是經營合同:
[OperationContract]
[WebInvoke(UriTemplate = "AddBook3/{Ans3}/{Ans4}/{Ans5}/{Ans6}/{Ans7}/{Ans8}/{Ans9}/{Ans10}/{Ans11}/{Ans12}/{customername}")]
void AddBook3(string Ans3, string Ans4, string Ans5, string Ans6, string Ans7, string Ans8, string Ans9, string Ans10, string Ans11, string Ans12, string customername);
而我的參數,這個URL如下:
http://localhost:80/IBookService.svc/AddBook/Morning$(7am-11am),/Set$Top$Box$or$Chatri$Connection/3/3/3424324,234234,24234,23423,/Diya$Aur$Baati,Sapne$Suhane$Ladakpan$Ke,Jodha$Akbar,Tumhari$Pakhi,Ek$Nayi$Pehaan,Yeh$Rishsta$Kya$Kehlata$Hai,Crime$Patrol,Taarak$Mehta,Sasural$Simar$Ka,---,---,---,---,---,---,---,---,---,/Suraj-Sandhya,Jodha-Akbar,Gopi-Ahem,Ishita-$-$Raman,Rachana$-$Gunjan,Akshara$-$Naitik,/234234/rtertert/pnme
當我經過一長串網址將無法正常工作。當我通過簡短的文本,然後它工作正常!爲什麼這樣?
爲什麼你不創建一個類來容納答案,並通過?或通過一個'列表答案'? –
christiandev
@christiandev在iOS應用 – pravin