輸出使用PHP

Question

陣列我有以下PHP代碼：

while($row = mysqli_fetch_array($query)) 
{ 
    $data = $row['name']; 
} 

我獲取所有與列名「姓名」在數據庫中的數據。我該如何輸出它？

["John", "Doe", "Deer"] 

Answer 1

您必須將$ data作爲數組類型變量。

while($row = mysqli_fetch_array($query)) 
{ 
    $data[] = $row['name']; 
} 

print_r($data); // required output 

Answer 2

while($row = mysqli_fetch_array($query)) 
{ 
    $data[] = $row['name']; 
} 

print_r($data); // output key wise display like 
Array ([0] => John [1] => Doe ) etc. 

但輸出你的建議，然後再補充json_encode()

print_r(json_encode($data)); // output like 
["John", "Doe", "Deer"] 

Answer 3

您需要使用json_encode（）方法來陣列中的jQuery的被接受。重新排列像下面的代碼..

$data = array(); 
while($row = mysqli_fetch_array($query)) 
{ 
    $data[] = $row['name']; 
} 

$new_array = json_encode($data); 
echo $new_array; // use 'echo' to print. The json_encode() convert $data array to string. 

Answer 4

$data = array(); 
while($row = mysqli_fetch_array($query)) 
{ 
    array_push($data, $row['name']); 
} 
echo json_encode($data);