查找和AWK命令替換

我有一個名爲sso_med.txt像查找和AWK命令替換

197: insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502683504',15,current_date, '502264160', current_date, '502264160'); 
198: insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502683504',16,current_date, '502264160', current_date, '502264160'); 
199: insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502689031',15,current_date, '502264160', current_date, '502264160');

文件，但我想讓它像

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502683504',15,current_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502683504',16,current_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502689031',15,current_date, '502264160', current_date, '502264160');

我想awk命令

awk '{gsub(/^\d+:\s/,""); print}' sso_med.txt

但它不工作。任何想法我正在做錯在正則表達式

來源

2017-05-25 sromit

'\ d'無法識別。用'[0-9]替換它' –

嘗試

awk '{gsub(/^[0-9]+: /,"")}1' file

來源

2017-05-25 19:15:43 karakfa

它工作:) thnx很多 – sromit

Downvoted缺乏解釋。請注意，與你的表情相比，提問者的表情是否正確/錯誤。 – SeldomNeedy

嘗試也sed的版本：

sed 's/^[0-9]*: //' Input_file

從0到9，然後替換起始位：空間與NULL並打印其餘部分。

來源

2017-05-25 19:43:10 RavinderSingh13

爲了避免該串中的其他地方去除相似的模式，使用sub，這只是替換模式的第一個實例：

# explanation of regex: "^"=line starts with pattern, "[0-9]+"=multiple numbers, ": "=colon and single space 
awk '{sub(/^[0-9]+: /, "", $0); print $0}'

實施例：

$ echo '197: insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values ('502683504',15,current_date, '502264160', current_date, '502264160');' | awk '{sub(/^[0-9]+: /, "", $0); print $0}'

結果：

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date,last_updated_by) values (502683504,15,current_date, 502264160, current_date, 502264160);

來源

2017-05-25 19:46:58 isosceleswheel

查找和AWK命令替換

回答

相關問題