給定一個返回[1,1] [2,3]，[5,1]的查詢，如何使用該結果？

Question

考慮：

class ThreadParticipations 
    scope :unread, lambda{ |user| where(:user_id => user.id, :read => false) } 
end 

ThreadParticipations 
    .unread(current_user) 
    .includes(:thread => :project) 
    .group('projects.id') 
    .count('threads.id') 

，輸出：

=> { 1 => 15, 3 => 10 } 

如何使用該結果來更新我的列表。鑑於該結果集1 & 3 project_ids，我怎麼能遍歷導致更新就像一個列表：

# iterates over @projects 
<div> 
<li>Project_id 1, unread count = 15</li> 
<li>Project_id 2, unread count = 0</li> 
<li>Project_id 3, unread count = 10</li> 
<li>Project_id 4, unread count = 0</li> 
<li>Project_id 5, unread count = 0</li> 
</div> 

感謝

Answer 1

不知道我理解，你只是想重複的哈希輸出html？

<ul> 
    <% { 1 => 15, 3 => 10 }.each_pair do |k,v| %> 
     <li>Project_id <%= k %>, unread count = <%= v%></li> 
    <% end %> 
</ul> 

edit：like that？

<ul> 
    <% [[1,1], [2, 3], [3, 15]].each do |project_id, unread_count| %> 
     <li>Project_id <%= project_id %>, unread count = <%= unread_count %></li> 
    <% end %> 
</ul> 

Answer 2

首先：您的HTML無效。 li元素進入ul的或ol的，而不是div的。您正在查找的代碼是：

<ul> 
    <% hash.each do |project_id, unread_count| %> 
    <li>Project_id <%= project_id %>, unread count = <%= unread_count %></li> 
    <% end %> 
</ul>