更改D和E的顏色

Question

從我以前的帖子中被盜，這是本文的目的。

具有用於引腳輸入的觸覺數字鍵盤的銀行金庫系統容易被盜賊濫用。小偷可以使用照相機，他們自己或甚至其他人查看4位數字引腳進入時的模式;因此他們不需要知道引腳的實際值，只需按下一系列按鈕即可進入系統。爲了克服這個致命的缺陷，可以使用具有數字鍵盤GUI的觸摸屏顯示器，每次輸入引腳時都會對鍵進行混洗，而不管它是否正確。

我試圖讓這個用戶很友好，所以我想將值D和E的顏色設置爲紅色，以使它們易於定位，但是當我嘗試調整代碼時，它會更改所有值的顏色。有誰知道解決辦法？任何和所有的幫助表示讚賞。 以下是我的代碼：

import tkinter as tk 
import random 

def code(position): 
    global pin 
    b = buttons[position] 
    value = b['text'] 

    if value == 'D': 
     # remove last element from `pin` 
     pin = pin[:-1] 
     # remove all from `entry` and put new `pin` 
     e.delete('0', 'end') 
     e.insert('end', pin) 

    elif value == 'E': 
     # check pin 
     if pin == "3529": 
      print("PIN OK") 
     else: 
      print("PIN ERROR!") 
      # clear pin 
      pin = '' 
      e.delete('0', 'end') 
    else: 
     # add number to `pin` 
     pin += value 
     # add number to `entry` 
     e.insert('end', value) 

    print("Current:", pin) 

    shuffle_buttons() 

def shuffle_buttons(): 
    for key in keys: 
     random.shuffle(key) 
    random.shuffle(keys) 
    for y, row in enumerate(keys): 
     for x, key in enumerate(row): 
      b = buttons[(x, y)] 
      b['text'] = key     

# --- main --- 

# keypad description 

keys = [ 
['1', '2', '3'], 
['4', '5', '6'], 
['7', '8', '9'], 
['D', '0', 'E'], 
] 

buttons = {} 

# create global variable 
pin = '' # empty string 

# init 
root = tk.Tk() 

# create `entry` to display `pin` 
e = tk.Entry(root, justify='right') 
e.grid(row=0, column=0, columnspan=3, ipady=5) 

# create `buttons` using `keys 
for y, row in enumerate(keys): 
    for x, key in enumerate(row): 
     position = (x, y) 
     b = tk.Button(root, text= key, command= lambda val=position: code(val)) 
     b.grid(row=y+1, column=x, ipadx=20, ipady=20) 

     buttons[position] = b 

shuffle_buttons() 

root.mainloop() 

Answer 1

使用config改變上的按鈕隨時shuffle_buttons()被稱爲值色：

import tkinter as tk 
import random 

def code(position): 
    global pin 
    b = buttons[position] 
    value = b['text'] 

    if value == 'D': 
     # remove last element from `pin` 
     pin = pin[:-1] 
     # remove all from `entry` and put new `pin` 
     e.delete('0', 'end') 
     e.insert('end', pin) 

    elif value == 'E': 
     # check pin 
     if pin == "3529": 
      print("PIN OK") 
     else: 
      print("PIN ERROR!") 
      # clear pin 
      pin = '' 
      e.delete('0', 'end') 
    else: 
     # add number to `pin` 
     pin += value 
     # add number to `entry` 
     e.insert('end', value) 

    print("Current:", pin) 

    shuffle_buttons() 

def shuffle_buttons(): 
    for key in keys: 
     random.shuffle(key) 
    random.shuffle(keys) 
    for y, row in enumerate(keys): 
     for x, key in enumerate(row): 
      b = buttons[(x, y)] 
      b['text'] = key 
      if key in ["D", "E"]: 
       b.config(fg="red") 
      else: 
       b.config(fg="black")    

# --- main --- 

# keypad description 

keys = [ 
['1', '2', '3'], 
['4', '5', '6'], 
['7', '8', '9'], 
['D', '0', 'E'], 
] 

buttons = {} 

# create global variable 
pin = '' # empty string 

# init 
root = tk.Tk() 

# create `entry` to display `pin` 
e = tk.Entry(root, justify='right') 
e.grid(row=0, column=0, columnspan=3, ipady=5) 

# create `buttons` using `keys 
for y, row in enumerate(keys): 
    for x, key in enumerate(row): 
     position = (x, y) 
     b = tk.Button(root, text= key, command= lambda val=position: code(val)) 
     b.grid(row=y+1, column=x, ipadx=20, ipady=20) 

     buttons[position] = b 

shuffle_buttons() 

root.mainloop()