2011-01-21 18 views
1

我指的是代碼片段從 這個職位所採取的第一個答案:Custom QuerySet and Manager without breaking DRY?Django QuerySet的初始化是如何工作的?

from django.db import models 
from django.db.models.query import QuerySet 

    class CustomQuerySetManager(models.Manager): 
     """A re-usable Manager to access a custom QuerySet""" 
     def __getattr__(self, attr, *args): 
      try: 
       return getattr(self.__class__, attr, *args) 
      except AttributeError: 
       return getattr(self.get_query_set(), attr, *args) 

     def get_query_set(self): 
      return self.model.QuerySet(self.model) 

這裏是模型:

from custom_queryset.models import CustomQuerySetManager 
from django.db.models.query import QuerySet 

class Inquiry(models.Model): 
    objects = CustomQuerySetManager() 

    class QuerySet(QuerySet): 
     def active_for_account(self, account): 
      self.filter(account = account, deleted=False, *args, **kwargs) 

self.model.QuerySet(self.model)總是收到一個相同的模型,但結果QuerySet依賴於輸入的QuerySet。例如:

Inquiry.objects.all()[:5].active_for_account(xyz),然後將active_for_account接收查詢集的5個項目,而在Inquiry.objects.all()[:7].active_for_account(xyz)active_for_account將收到一個查詢集的7個項目。這裏是堆棧軌跡:

Inquiry.objects.all()[:5].active_for_account(xyz) 
    return getattr(self.get_query_set(), attr, *args), 
     return self.model.QuerySet(self.model) (1) 

Inquiry.objects.all()[:7].active_for_account(xyz) 
    return getattr(self.get_query_set(), attr, *args), 
     return self.model.QuerySet(self.model) (2) 

爲什麼在(1)和(2)的結果不同?

回答

1

我不完全確定你在問什麼。

Inquiry.objects.all()[:5]不給你提供對象,它給你一個包含五個元素的QuerySet對象。