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我有以下HTML。自動提交下拉選擇表單*無*點擊提交按鈕？ AJAX/PHP
目前它依靠用戶點擊'轉到'按鈕來提交表單。
是否有可能改變它，以便每次用戶選擇下拉選項時提交？
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Employees by Department</title>
<script src="ajax.js" type="text/javascript"></script>
<script src="dept.js" type="text/javascript"></script>
<style type="text/css" media="all">@import "style.css";</style>
</head>
<body>
<!-- dept_form_ajax.html -->
<p>Select a department and click 'GO' to see the employees in that department.</p>
<form action="dept_results.php" method="get" id="dept_form">
<p>
<select id="did" name="did">
<option value="1">Human Resources</option>
<option value="2">Accounting</option>
<option value="3">Marketing</option>
<option value="4">Redundancy Department</option>
</select>
<input name="go" type="submit" value="GO" />
</p>
</form>
<select id="results"></select>
</body>
</html>
爲了記錄在案，這裏是我的dept.js文件內容：
// dept.js
/* This page does all the magic for applying
* Ajax to an employees listing form.
* The department_id is sent to a PHP
* script which will return data in HTML format.
*/
// Have a function run after the page loads:
window.onload = init;
// Function that adds the Ajax layer:
function init() {
// Get an XMLHttpRequest object:
var ajax = getXMLHttpRequestObject();
// Attach the function call to the form submission, if supported:
if (ajax) {
// Check for DOM support:
if (document.getElementById('results')) {
// Add an onsubmit event handler to the form:
document.getElementById('dept_form').onsubmit = function() {
// Call the PHP script.
// Use the GET method.
// Pass the department_id in the URL.
// Get the department_id:
var did = document.getElementById('did').value;
// Open the connection:
ajax.open('get', 'dept_results_ajax.php?did=' + encodeURIComponent(did));
// Function that handles the response:
ajax.onreadystatechange = function() {
// Pass it this request object:
handleResponse(ajax);
}
// Send the request:
ajax.send(null);
return false; // So form isn't submitted.
} // End of anonymous function.
} // End of DOM check.
} // End of ajax IF.
} // End of init() function.
// Function that handles the response from the PHP script:
function handleResponse(ajax) {
// Check that the transaction is complete:
if (ajax.readyState == 4) {
// Check for a valid HTTP status code:
if ((ajax.status == 200) || (ajax.status == 304)) {
// Put the received response in the DOM:
var results = document.getElementById('results');
results.innerHTML = ajax.responseText;
// Make the results box visible:
results.style.display = 'block';
} else { // Bad status code, submit the form.
document.getElementById('dept_form').submit();
}
} // End of readyState IF.
} // End of handleResponse() function.
這裏任何指針非常感謝。
認爲這是我所追求的。你可以在編輯我的'dept.js'文件時解釋我包含這個的位置嗎？非常感謝 – michaelmcgurk 2012-02-15 06:46:12
這沒有奏效。我會看看JS錯誤控制檯並報告回來。感謝您的幫助。 – michaelmcgurk 2012-02-15 06:50:34
之前，我甚至從菜單中選擇：'錯誤：失蹤）參數列表 源文件：http：//localhost/dept.js 行：50，列：4 源代碼： } // DOM檢查結束。 ' – michaelmcgurk 2012-02-15 06:53:31