如何有條件地移動排隊？

-1

test = 
more text more text more text more text 
more text more text more text more text 
... etc.... 
more text more text more text more text 
more text more text more text more text 
1 text 
test2 = 
more text more text more text more text 
more text more text more text more text 
3 more text

等

我想要做的是移動線'開始的數並附他們的第一行後發現（倒退），與「= \ s」的

結束預計產出：

test = 1 text 
more text more text more text more text 
more text more text more text more text 
... etc.... 
more text more text more text more text 
more text more text more text more text 
test2 = 3 more text 
more text more text more text more text 
more text more text more text more text

我不知道該怎麼做。
有人可以幫助我嗎？

來源

2013-09-23 Reman

使用:global，:norm，:move並有可能使用搜索作爲目標Ex命令：

:g/^\d/m?.*=$|norm kJ

擊穿：

:g/pattern/command " executes command for every line matching pattern 
^\d    " pattern for "lines that start with a number" 
m?.*=$    " move matched line to right below the first 
        " line ending with = upward 
|     " separator between Ex commands 
norm    " execute normal mode command 
kJ     " go to line above and join

來源

2013-09-23 14:45:43 romainl

與我的宏觀相同的想法。但是：g命令會比宏命令好。 +1 – Kent

Vim golf：'：g/^ \ d/m？。* = $ | -j' –

非常感謝romainl！ – Reman

宏可以幫助...

/^\d<cr>:.m?=<cr>kJ

簡短說明：

/^\d " find line beginning with number 
:.m?= " move current line under the previous line with (=) 
kJ  "move cursor back to the line with (=), and join the next

，它正在像：

（看來我輸入一個更?最後n在截圖中，但我不會再記錄它。）

enter image description here

來源

2013-09-23 14:41:31 Kent

太感謝您在肯特！非常好的解決方案，但正如你所提到的，也許Romainl的解決方案更容易。 – Reman

如何有條件地移動排隊？

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