檢查網站的相互鏈接

Question

我試圖讓一個腳本，將加載所需的URL（由用戶輸入），並在他們的域上我的網站上發佈，如果該網頁的鏈接回到我的域名查詢。我不是很有經驗的正則表達式，這是我到目前爲止有：

$loaded = file_get_contents('http://localhost/small_script/page.php'); 
// $loaded will be equal to the users site they have submitted 
$current_site = 'site2.com'; 
// $current_site is the domain of my site, this the the URL that must be found in target site 
$matches = Array(); 
$find = preg_match_all('/<a(.*?)href=[\'"](.*?)[\'"](.*?)\b[^>]*>(.*?)<\/a>/i', $loaded, $matches); 

$c = count($matches[0]); 
$z = 0; 
while($z<$c){ 
    $full_link = $matches[0][$z]; 
    $href = $matches[2][$z]; 
    $z++; 

    $check = strpos($href,$current_site); 
    if($check === false) { 

    }else{ 
    // The link cannot have the "no follow" tag, this is to check if it does and if so, return a specific error 
    $pos = strpos($full_link,'no follow'); 

    if($pos === false) { 
    echo $href; 
    } 
     else { 
    //echo "rel=no follow FOUND"; 
    } 

    } 

} 

正如你可以看到，這是相當混亂，我完全相信在那裏的領導。我希望有人能夠給我一個小巧，快速和簡潔的腳本，能夠完成我所嘗試的。由用戶輸入

檢查

1. 裝載指定的URL，如果指定的URL鏈接回到我的網站（如果沒有，返回錯誤代碼＃1）
2. 如果鏈接是存在的，檢查「沒有後續」，如果發現返回錯誤代碼＃2
3. 如果一切正常，設置爲true的變量，這樣我就可以繼續其它功能（如顯示他們的鏈接我的網頁上）

Answer 1

這是代碼:) 幫助

<?php 

$my_url = 'http://online.bulsam.net'; 
$target_url = 'http://www.bulsam.net'; 
$userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)'; 

// make the cURL request to $target_url 
$ch = curl_init(); 
curl_setopt($ch, CURLOPT_USERAGENT, $userAgent); 
curl_setopt($ch, CURLOPT_URL,$target_url); 
curl_setopt($ch, CURLOPT_FAILONERROR, true); 
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); 
curl_setopt($ch, CURLOPT_AUTOREFERER, true); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true); 
curl_setopt($ch, CURLOPT_TIMEOUT, 10); 
$html= curl_exec($ch); 
if (!$html) { 
    echo "<br />cURL error number:" .curl_errno($ch); 
    echo "<br />cURL error:" . curl_error($ch); 
    exit; 
} 

// parse the html into a DOMDocument 
$dom = new DOMDocument(); 
@$dom->loadHTML($html); 


// grab all the on the page 
$xpath = new DOMXPath($dom); 
$hrefs = $xpath->evaluate("/html/body//a"); 

// find result 
$result = is_my_link_there($hrefs, $my_url); 

if ($result == 1) { 

    echo 'There is no link!!!'; 
} elseif ($result == 2) { 

    echo 'There is, but it is NO FOLLOW !!!'; 
} else { 

    // blah blah blah 
} 

// used functions 

function is_my_link_there($hrefs, $my_url) { 

    for ($i = 0; $i < $hrefs->length; $i++) { 

     $href = $hrefs->item($i); 

     $url = $href->getAttribute('href'); 

     if ($my_url == $url) { 

      $rel = $href->getAttribute('rel'); 

      if ($rel == 'nofollow') { 

       return 2; 
      } 

      return 3; 
     } 
    } 

    return 1; 
}