如何使用Jersey客戶端POST方法提交數據

Question

我是澤西島的新手。我需要實現一個Jersey客戶端來使用POST方法提交數據。 curl命令是：

curl -d '{"switch": "00:00:00:00:00:00:00:01", "name":"flow-mod-1", "priority":"32768", "ingress-port":"1","active":"true", "actions":"output=2"}' http://localhost:8080/wm/staticflowentrypusher/json 

所以我試圖找出如何使用Jersey客戶端來實現上述curl命令。

到目前爲止，我已經做了：

public class FLClient { 

private static Client client; 
private static WebResource webResource; 
private static String baseuri = "http://localhost:8080/wm/staticflowentrypusher/json"; 
private static ClientResponse response; 
private static String output = null; 

public static void main(String[] args) { 
    try { 

     client = Client.create(); 

     webResource = client.resource(baseuri); 

        // implement POST data 

    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
} 

} 

有人可以幫助我呢？

Answer 1

現在我明白了。這裏是我的解決方案：

public static void main(String[] args) { 

    try { 
     Client client = Client.create(); 

     WebResource webResource = client.resource(baseuri); 

     String input = "{\"switch\": \"00:00:00:00:00:00:00:01\", " 
       + "\"name\":\"flow-mod-1\", \"priority\":\"32768\", " 
       + "\"ingress-port\":\"1\",\"active\":\"true\", " 
       + "\"actions\":\"output=2\"}"; 

     // POST method 
     ClientResponse response = webResource.accept("application/json") 
       .type("application/json").post(ClientResponse.class, input); 

     // check response status code 
     if (response.getStatus() != 200) { 
      throw new RuntimeException("Failed : HTTP error code : " 
        + response.getStatus()); 
     } 

     // display response 
     String output = response.getEntity(String.class); 
     System.out.println("Output from Server .... "); 
     System.out.println(output + "\n"); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 

} 

Answer 2

如果你想發佈一個JSON體內，這是一個更好的方法。

ClientConfig clientConfig = new DefaultClientConfig();    
clientConfig.getFeatures().put(JSONConfiguration.FEATURE_POJO_MAPPING, Boolean.TRUE);  
client = Client.create(clientConfig); 

WebResource webResource = client.resource(baseuri); 

Map<String,Object> postBody = new HashMap<String,Object>(); 
//put switch, name,priority.... 
ClientResponse response = webResource.accept("application/json") 
       .type("application/json").post(ClientResponse.class, postBody); 

記住，你必須包括jersey-json

Answer 3

對於未來的用戶，與jersey事物的新版本已經改變，所以做這樣的POST方法的方式是：

• 適用版本1.x（@Li'answer）：

  WebResource webResource = client.resource(baseuri); 
  
  String input = "..."; 
  
  ClientResponse response = webResource.accept("application/json") 
       .type("application/json").post(ClientResponse.class, input); 
  

• 對於2.x版本：

  WebTarget webTarget = client.target(baseuri); 
  
  String input = "..."; 
  
  Response response = webTarget.request("application/json").post(Entity.json(input)); 
  

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