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我一直在嘗試過去的幾個小時內在電子郵件中創建一個動態表..我一直unsuccuessful我已經試圖創建表進出身體變量和回聲它內,但我沒有成功,我已經放置我的代碼bellow .. anyhelp將非常感謝..所有即時通訊要做的是創建一個表中的一些MySQL數據,然後將其發送給一些客戶端..這只是一個運行我一直attemoting完成電子郵件中的動態表
$link = mysql_connect('localhost', 'root', '');
mysql_select_db('netbookdb');
$sql="SELECT * FROM rep_log WHERE s_date = '2012-05-31'";
$result=mysql_query($sql, $link);
$date=date('dmy');
require("../PHPMailer/class.phpmailer.php");
$mail = new PHPMailer();$mail = new PHPMailer();
$mail->IsSMTP(); // set mailer to use SMTP
$mail->Host = "smtp"; // specify main and backup server
$mail->From = "[email protected]";
$mail->FromName = "Ict Devices";
$mail->AddAddress("[email protected]", "Matthew");
$mail->Subject = "Damage Log Report";
$mail->IsHTML(true);
$var='xlsx';
$date=date('dmy.');
$mail->Body = " while($rows=mysql_fetch_array($result)){
$cases=$rows['cases'];
$hg=$rows['hg'];
$surname=$rows['surname'];
$firstname=$rows['firstname'];
$claim=$rows['claim'];
$damage=$rows['damage'];
$cost=$rows['cost'];
}";
$mail->AltBody="Please Use a Html Compaible Email Veiwer";
if(!$mail->Send())
{
echo "Error sending: " . $mail->ErrorInfo;;
}
else
{
echo "Letter is sent";
}