我試圖將上傳的圖像插入與用戶的user_id從會話變量的MySQL。我發現了一個在線教程,並更改如下它:使用php插入圖像到mysql
<?php
require_once('../Login/includes/session_timeout_db.inc.php');
$dbuser="";
$dbname="";
$dbpass="";
$dbserver="";
$con = mysql_connect($dbserver,$dbuser,$dbpass);
if (!$con){ die('Could not connect: ' . mysql_error()); }
mysql_select_db($dbname, $con);
// Make sure the user actually
// selected and uploaded a file
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {
// Temporary file name stored on the server
$tmpName = $_FILES['image']['tmp_name'];
// Read the file
$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));
$data = addslashes($data);
fclose($fp);
// Create the query and insert
// into our database.
$query = "INSERT INTO images, owner_id";
$query .= "(image) VALUES ('$data', '.$_SESSION['id'].')";
$results = mysql_query($query, $link);
// Print results
print "Thank you, your file has been uploaded.";
}
else {
print "No image selected/uploaded";
}
// Close our MySQL Link
mysql_close($link);
?>
<!DOCTYPE html PUBLIC 「-//W3C//DTD XHTML 1.0 Strict//EN」
「http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd」>
<html xmlns=」http://www.w3.org/1999/xhtml」>
<head>
<meta http-equiv=」Content-Type」 content=」text/html; charset=utf-8」 />
<title>Manage Tasks</title>
<link rel="stylesheet" type="text/css" href="../allcss/style.css" />
</head>
<body>
<?php
require('../Login/includes/header.inc.php');
?>
<div id="content">
<form enctype="multipart/form-data" action="" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="102400" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
</div>
</body>
</html>
我有錯我的查詢的第二行:
$query = "INSERT INTO images, owner_id";
$query .= "(image) VALUES ('$data', '.$_SESSION['id'].')";
$results = mysql_query($query, $link);
*錯誤是解析錯誤:語法錯誤,意外T_ENCAPSED_AND_WHITESPACE,期望T_STRING或T_VARIABLE或T_NUM_STRING 28行*
有人可以請幫忙嗎?
感謝adnvance