MYSQL總和科拉姆並選擇進行了歸納

Question

嘿，你在那裏的各行，

我嘗試寫總結一組數據成員的數量被允許使用的查詢，並在相同的查詢選擇單個成員允許使用的數據量。

這是我此刻的查詢

SELECT (groups.extra_space + DataPlan.total_disk_space_limit) AS total_space, 
    SUM(User.disk_space_limit) AS total_allocated, 
    User.id, User.first_name, 
    User.last_name, 
    User.disk_space_limit 
FROM groups INNER JOIN users AS User ON (groups.id = User.group_id) 
INNER JOIN data_plans AS DataPlan ON (groups.data_plan_id = DataPlan.id 
AND User.group_id = Group_id) WHERE groups.id = 24; 

的數據設置該返回是：

+-------------+-----------------+----+------------+-----------+------------------+ 
| total_space | total_allocated | id | first_name | last_name | disk_space_limit | 
+-------------+-----------------+----+------------+-----------+------------------+ 
|   300 |    82 | 22 | Big  | Bird  |    0 | 
+-------------+-----------------+----+------------+-----------+------------------+ 

我想將數據設置爲沿的線條更...

+-------------+-----------------+----+------------+-----------+------------------+ 
| total_space | total_allocated | id | first_name | last_name | disk_space_limit | 
+-------------+-----------------+----+------------+-----------+------------------+ 
|   300 |    82 | 22 | Big  | Bird  |    0 | 
|   300 |    82 | 23 | Cookie  | Monster |    11 | 
|   300 |    82 | 24 | Oscar  | Grouch |    32 | 
|   300 |    82 | 25 | Count  | Count  |    19 | 
|   300 |    82 | 26 | Snuffel | Ufogus |    20 | 
+-------------+-----------------+----+------------+-----------+------------------+ 

我知道這將很容易做2個查詢，但我真的很想學習如何做到一個。

任何幫助將不勝感激！

謝謝！

Answer 1

或許只需添加一個group by User.id子句您當前查詢

編輯的末尾：下面是一個子查詢的例子：

SELECT (groups.extra_space + DataPlan.total_disk_space_limit) AS total_space, 
    (select SUM(users.disk_space_limit) from users WHERE users.group_id = groups.id) AS total_allocated, 
    User.id, User.first_name, 
    User.last_name, 
    User.disk_space_limit 
FROM groups INNER JOIN users AS User ON (groups.id = User.group_id) 
INNER JOIN data_plans AS DataPlan ON (groups.data_plan_id = DataPlan.id 
AND User.group_id = Group_id) WHERE groups.id = 24;