從多個鏈接中獲取數據

Question

我有一個PHP代碼，它將從「level0 nav-1 active parent」的類名檢索數據。有沒有一種方法可以提供一系列鏈接，併爲每個鏈接的循環數組使用稍微不同的類名，而無需爲10個鏈接重複相同的代碼？

是這樣的： 第一連桿（https://www.postme.com.my/men-1.html） - 使用類（ 「0級NAV-1活性母體」） 二（https://www.postme.com.my/women.html） - 使用類（ 「0級NAV-2活性母體」） 三（https://www.postme.com.my/children.html） - 使用類（「level0 nav-3 active parent」）

注意遞增的nav-＃？

這是PHP代碼：

<?php 
header('Content-Type: text/html; charset=utf-8'); 
$grep = new DoMDocument(); 
@$grep->loadHTMLFile("https://www.postme.com.my/men-1.html"); 

$finder = new DomXPath($grep); 
$classCat = "level0 nav-1 active parent"; 

$nodesCat = $finder->query("//*[contains(@class, '$classCat')]"); 

$i = 0; 

    foreach ($nodesCat as $node) { 
    $span = $node->childNodes; 
    $replace = str_replace("Items 1-12 of", "",$span->item(1)->nodeValue); 

    echo $replace. " : "; 
    } 

    // Check another link using class name of "level0 nav-2 active parent" 
    //repeat code 

    @$grep->loadHTMLFile("https://www.postme.com.my/women.html"); 

$finder = new DomXPath($grep); 
$classCat = "level0 nav-2 active parent"; 

$nodesCat = $finder->query("//*[contains(@class, '$classCat')]"); 

$i = 0; 

    foreach ($nodesCat as $node) { 
    $span = $node->childNodes; 
    $replace = $span->item(1)->nodeValue; 

    echo $replace. " : "; 
    } 
//check another link with class name "level0 nav-3 active parent". 
//notice the incrementing nav-#? 
//I don't want to make the code long just because each link is using a slightly different class name to refer to the data. 
?> 

感謝

Answer 1

我會做的就是讓這些鏈接（<li>），這是<ul id="nav">的父。然後從那裏。提取值。例如：

$dom = new DOMDocument(); 
@$dom->loadHTMLFile('https://www.postme.com.my/men-1.html'); 
$xpath = new DOMXpath($dom); 

$categories = $xpath->query('//ul[@id="nav"]/li'); 

foreach($categories as $category) { 
    echo $xpath->query('./a/span', $category)->item(0)->nodeValue . '<br/>'; 
}