編程邏輯！ ：O

Question

因爲想要看似合理的編程邏輯而難以忍受。

在SSIS的腳本任務中。需要做一些數據轉換..以下..

switch(LeadTime) 
{ 

case: 1 

WM1 = DAY1 
WM2 = DAY2 
WM3 = DAY3 
WM4 = DAY4 
WM5 = DAY5 
WM6 = DAY6 
WM7 = DAY7 


case: 2 

WM1 = DAY1 + DAY2 
WM2 = DAY2 + DAY3 
WM3 = DAY3 + DAY4 
WM4 = DAY4 + DAY5 
WM5 = DAY5 + DAY6 
WM6 = DAY6 + DAY7 
WM7 = DAY7 + DAY1 


case: 3 


WM1 = DAY1 + DAY2 + DAY3 
WM2 = DAY2 + DAY3 + DAY4 
WM3 = DAY3 + DAY4 + DAY5 
WM4 = DAY4 + DAY5 + DAY6 
WM5 = DAY5 + DAY6 + DAY7 
WM6 = DAY6 + DAY7 + DAY1 
WM7 = DAY7 + DAY1 + DAY2 


.................. 

case: 7 

WM1 = DAY1 + DAY2 + DAY3 + DAY4 + DAY5 + DAY6 + DAY7 
WM2 = DAY2 + DAY3 + DAY4 + DAY5 + DAY6 + DAY7 + DAY1 
WM3 = DAY3 + DAY4 + DAY5 + DAY6 + DAY7 + DAY1 + DAY2 
WM4 = DAY4 + DAY5 + DAY6 + DAY7 + DAY1 + DAY2 + DAY3 
WM5 = DAY5 + DAY6 + DAY7 + DAY1 + DAY2 + DAY3 + DAY4 
WM6 = DAY6 + DAY7 + DAY1 + DAY2 + DAY3 + DAY4 + DAY5 
WM7 = DAY7 + DAY1 + DAY2 + DAY3 + DAY4 + DAY5 + DAY6 


} 

我怎樣才能建立一個循環，使其良好的編程？我在虧損，因爲它在中間價值後從兩端增加..

這是我所能做的！ ：O

case: 7 

for(int i=0;i<LeadTime;i++) 
{ 
WM1 += Array[i]; 
WM2 += Array[i]; 
... 
WM7 += Array[i]; 
} 

Answer 1

像這樣的東西應該爲所有情況下工作（假設數組是從零開始）：

for(int i=0;i<LeadTime;i++) 
{ 
    WM1 += Array[(0+i)%7]; 
    WM2 += Array[(1+i)%7]; 
    ... 
    WM7 += Array[(6+i)%7]; 
} 

Answer 2

您可以使用模數進行換行。這應該爲所有工作：

WM = new int[7]; 
for (int i = 0; i < LeadTime; i++) { 
    for (int j = 0; j < WM.Length; j++) { 
    WM[j] += Array[(i + j) % 7]; 
    } 
} 

Answer 3

你想要做的是創造，你可以調用一個函數不同的情況。

function foo(int LeadTime) { 
    for(int i=0; i < LeadTime; i++){ 
     int k = i; 
     for (int j = 0; j < LeadTime; j++){ 
      if (k > 7) { k = 1; } 
      wm[i] += day[k]; 
      k++; 
     } 
    } 
} 

Answer 4

我很快想出了這段代碼。 Bascially你將不得不做一個嵌套循環

string[] days = new string[] { "DAY1", "DAY2", "DAY3", "DAY4", "DAY5", "DAY6", "DAY7" }; 

      List<string> res = new List<string>(); 
      res.Add(string.Empty); 

      int Leadtime = 7; 

      for (int i = 1; i <= Leadtime; i++) 
      { 
       res.Add(string.Empty); 
       int tmp = i + Leadtime - 1; 

       for (int x = i; x <= tmp; x++) 
       { 
        if (x > Leadtime) { x = 1; tmp = i-1; } 
        res[i] += " " + days[x-1]; 
       } 

      } 

      foreach (string s in res) 
      { 
       Console.WriteLine(s); 
      } 

      Console.ReadKey(); 

結果：

DAY1 DAY2 DAY3 DAY4 DAY5 DAY6 DAY7 
DAY2 DAY3 DAY4 DAY5 DAY6 DAY7 DAY1 
DAY3 DAY4 DAY5 DAY6 DAY7 DAY1 DAY2 
DAY4 DAY5 DAY6 DAY7 DAY1 DAY2 DAY3 
DAY5 DAY6 DAY7 DAY1 DAY2 DAY3 DAY4 
DAY6 DAY7 DAY1 DAY2 DAY3 DAY4 DAY5 
DAY7 DAY1 DAY2 DAY3 DAY4 DAY5 DAY6