用於覆蓋多繼承函數的語法

Question

class A 
{ 
    protected: 
    void func1() //DO I need to call this virtual? 
}; 

class B 
{ 
    protected: 
    void func1() //and this one as well? 
}; 

class Derived: public A, public B 
{ 
    public: 

    //here define func1 where in the code there is 
    //if(statement) {B::func1()} else {A::func1()} 
}; 

如何覆蓋func1？或者你可以定義它

class Derived: public A, public B 
{ 
    public: 

    void func1() 
}; 

沒有任何虛擬或重寫？我不明白可訪問性。謝謝。

Answer 1

倫納德烈，

覆蓋，你可以簡單地用相同名稱聲明的功能，實現在你需要一個變量的代碼中的註釋功能傳遞給衍生FUNC1（）

對於例如：

#include <iostream> 

using namespace std; 

class A 
{ 
    protected: 
    void func1() { cout << "class A\n"; } //DO I need to call this virtual? 
}; 

class B 
{ 
    protected: 
    void func1() { cout << "class B\n"; } //and this one as well? 
}; 

class Derived: public A, public B 
{ 
    public: 

    //here define func1 where in the code there is 
    //if(statement) {B::func1()} else {A::func1()} 
    void func1(bool select = true) 
    { 
     if (select == true) 
     { 
      A::func1(); 
     } 
     else 
     { 
      B::func1(); 
     } 
    } 
}; 
int main() 
{ 
    Derived d; 
    d.func1();   //returns default value based on select being true 
    d.func1(true);  //returns value based on select being set to true 
    d.func1(false);  // returns value base on select being set to false 
    cout << "Hello World" << endl; 

    return 0; 
} 

這應該做你在找什麼，我已經使用了一個布爾值，因爲只有2個可能的版本，但是你可以使用一個enum或int適合的情況下，更多的OPTIO納秒。