循環在獲得輸入前完成一個循環，如何解決？

Question

while (1) 
{ 
    cout << "Enter the Citizen ID number of the worker or Enter 0 to exit:" << endl; 
    getline (cin, j); 
    for (i=0; i<5; i++) 
    { 
     if (workers[i]->IDno == j) 
     { 
      wFind = 1; 
      cout << "Choose your option:" << endl; 
      cout << "1- Display all details of the worker" << endl; 
      cout << "2- Display number of the days worker delayed" << endl; 
      cout << "3- Display number of the days worker missed" << endl; 
      cin >> k; 
      switch (k) 
      { 
      case 1: 
       workers[i]->AWorker(); 
       break; 
      case 2: 
       cout << workers[i]->TotalDaysDelayed() << endl; 
       break; 
      case 3: 
       cout << workers[i]->TotalDaysMissed() << endl; 
       break; 
      default: 
       break; 
      } 
     } 
     else 
      wFind = 0; 
    } 

    if (wFind == 0) 
     cout << "ERROR: No worker has the ID number that you typed!" << endl; 
} 

注：wFind初始化爲2。

當我執行這個代碼，我總是得到這樣的輸出：

Enter the Citizen ID number of the worker or Enter 0 to exit:
ERROR: No worker has the ID number that you typed!
Enter the Citizen ID number of the worker or Enter 0 to exit:

有趣的是，我的代碼可以讓我輸入的字符串j之前完成循環週期。這怎麼可能，我能做些什麼來解決它？

Answer 1

cin >> k;不會吃換行符。你需要調用std::getline之後才能使用換行符。

如果你在循環的第一次迭代時遇到了問題，那麼我會推測你的代碼在此之上，也不會吃掉換行符。