0
function startMatch(){
Wbrook0 = new component(50, 50, "pieces/WhiteBrook.png", 0, 0, "piece", "Wbro0");
Wknight0 = new component(50, 50, "pieces/WhiteKnight.png", 50, 0, "piece", "Wknight0");
Wbishop0 = new component(50, 50, "pieces/WhiteBishop.png", 100, 0, "piece", "Wbis0");
Wqueen = new component(50, 50, "pieces/WhiteQueen.png", 150, 0, "piece", "Wque");
Wking = new component(50, 50, "pieces/WhiteKing.png", 200, 0, "piece", "Wking");
Wbishop1 = new component(50, 50, "pieces/WhiteBishop.png", 250, 0, "piece", "Wbis1");
Wknight1 = new component(50, 50, "pieces/WhiteKnight.png", 300, 0, "piece", "Wknight1");
Wbrook1 = new component(50, 50, "pieces/WhiteBrook.png", 350, 0, "piece", "Wbro1");
}
function helpme(){
console.log(component.length); //This will output 7, which is how many parameters component has
console.log(Bking.constructor.length); //Same here
}
function component(width, height, color, x, y, type, me){
//Mostly unrelated stuff, the stuff I left just defines the parameters
this.width = width;
this.height = height;
this.x = x;
this.y = y;
this.id = me;
}
是否可以找到所有組件參數的所有當前值? (即如果我插入「x」到代碼,我問到console.log(),它會打印0,50,100,150,200,300和350.是否有可能將值與構造函數的參數進行比較?
我知道我可以爲每一個做console.log(Wbrook.x),但我已經有32個這樣做了,爲了做我想做的事情,我還需要做y和id,並且在我弄糟這個之前,我想我會看看是否有更簡單的方法。
道歉,如果該說明和標題是模糊的,我沒有與構造多少經驗呢。先謝謝了。
這是我的看法:https://jsfiddle.net/sfwhtqwy/ –