2014-03-04 87 views
1

我在我的web應用程序中使用Spring安全3.2.0。春季安全 - 記住我認證與多個身份驗證提供商

我有兩個安全角色:具有存儲在數據庫中的憑證的用戶和存儲在配置文件中的憑證的管理員。

它工作正常,直到我打開記得我身份驗證。這裏是我的security.xml配置:

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:security="http://www.springframework.org/schema/security" 
     xsi:schemaLocation="http://www.springframework.org/schema/beans 
     http://www.springframework.org/schema/beans/spring-beans-4.0.xsd 
    http://www.springframework.org/schema/security 
    http://www.springframework.org/schema/security/spring-security-3.2.xsd"> 

    <security:global-method-security secured-annotations="enabled"/> 

    <security:http auto-config="true"> 
     <security:remember-me key="myAppKey" user-service-ref="adminSrv"/> 
     <security:remember-me key="myAppKey" user-service-ref="jdbcUserSrv"/> 
     <security:form-login login-page="/login" default-target-url="/" 
      authentication-failure-url="/loginfailed" /> 
     <security:logout logout-success-url="/logout"/> 
    </security:http> 

    <security:authentication-manager> 
     <security:authentication-provider> 
      <security:jdbc-user-service data-source-ref="dataSource" id="jdbcUserSrv" 
             users-by-username-query="/* SQL query */" 
             authorities-by-username-query="/* Another SQL query */" 
        /> 
     </security:authentication-provider> 
     <security:authentication-provider> 
      <security:user-service id="adminSrv"> 
       <security:user name="admin" authorities="ROLE_ADMIN" password="passwd"/> 

      </security:user-service> 
     </security:authentication-provider> 
    </security:authentication-manager> 
</beans> 

當我以管理員身份登錄它去罰款。

當我嘗試以用戶身份登錄,它拋出的異常的j_spring_security_check:

HTTP ERROR 500 

Problem accessing /mercury/j_spring_security_check. Reason: 

    user1 
Caused by: 

org.springframework.security.core.userdetails.UsernameNotFoundException: user1 
    at org.springframework.security.provisioning.InMemoryUserDetailsManager.loadUserByUsername(InMemoryUserDetailsManager.java:113) 
    at org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices.onLoginSuccess(TokenBasedRememberMeServices.java:178) 
    at org.springframework.security.web.authentication.rememberme.AbstractRememberMeServices.loginSuccess(AbstractRememberMeServices.java:262) 
    at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:324) 
    at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.successfulAuthentication(AbstractAuthenticationProcessingFilter.java:298) 
    at org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:235) 
    at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342) 
    at org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:110) 
    at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342) 
    at org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:87) 
    at org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342) 
    at org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192) 
    at org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:160) 
    at org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:344) 
    at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:261) 
    at org.mortbay.jetty.servlet.ServletHandler$CachedChain.doFilter(ServletHandler.java:1157) 
    at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:388) 
    at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) 
    at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:182) 
    at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:765) 
    at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:418) 
    at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:230) 
    at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114) 
    at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) 
    at org.mortbay.jetty.Server.handle(Server.java:326) 
    at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:542) 
    at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:943) 
    at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:756) 
    at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:218) 
    at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:404) 
    at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:410) 
    at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:582) 

但是如果認證成功,如果我打開我的應用程序的索引頁它顯示登錄爲「USER1」。

如果remember-me配置爲jdbcUserSrv之前配置爲adminSrv然後錯誤出現「admin」用戶。

目前的配置工作正常,沒有remember-me選項,但我需要它們啓用。

請指教我如何避免這些錯誤。

+0

據我所知,春天需要你記住,我哪預計設置了一個UserDetailsS​​ervice。在春季文檔中提到,http://docs.spring.io/spring-security/site/docs/3.0.x/reference/remember-me.html – Lucky

回答

2

擁有兩個記憶我元素就是互相重疊。擁有多個UserDetailsS​​ervice實例也會讓你陷入困境。例如,我假設您可能有與您的用戶相關的數據。如果在內存和jdbc UserDetailsS​​ervice實例中都存在名爲admin的用戶,那麼您如何知道數據屬於哪個管理員用戶?出於這個原因,最好使用一個UserDetailsS​​ervice。

或者,您可以創建一個委託給多個UserDetailsS​​ervice實例的UserDetailsS​​ervice。例如:

public class DelegatingUserDetailsService implements UserDetailsService { 
    private final List<UserDetailsService> userDetailsServices; 

    public DelegatingUserDetailsService(
      List<UserDetailsService> userDetailsServices) { 
     this.userDetailsServices = userDetailsServices; 
    } 

    public UserDetails loadUserByUsername(String username) 
      throws UsernameNotFoundException { 
     RuntimeException last = null; 
     for(UserDetailsService uds : userDetailsServices) { 
      try { 
       return uds.loadUserByUsername(username); 
      } catch(RuntimeException error) { 
       last = error; 
      } 
     } 
     throw last; 
    } 
} 

然後你就可以擁有記得,我用它來代替:

<bean id="delegateUds" class="DelegatingUserDetailsService"> 
    <constructor-arg> 
     <list> 
      <ref bean="jdbcUserSrv"/> 
      <ref bean="adminSrv"/> 
     </list> 
    </constructor-arg> 
</bean> 
<security:http auto-config="true"> 
    <security:remember-me key="myAppKey" user-service-ref="delegateUds"/> 
    <security:form-login login-page="/login" default-target-url="/" 
     authentication-failure-url="/loginfailed" /> 
    <security:logout logout-success-url="/logout"/> 
</security:http> 
+0

感謝您的回覆。我決定實現我自己的UserDetailsS​​ervice,但您的解決方案也非常有用。 – Nailgun

相關問題