在導軌中選擇一個字符串的多個部分

Question

我想分割一個字符串並遇到麻煩。

在軌道，我有一個很長的字符串，並在其中，這樣的事情會發生3-6次：

bunchofotherstringstuffandcharacters"hisquote":"The most important aspect of the painting was the treatment of lighting.","lp":andthenalotmorestringandcharacters 

我要切出「繪畫的最重要的方面是治療的照明「，以及落在他的引用和lp之間的其他實例。

的「hisquote」自帶之前，它是唯一我想要的字符串，因此是自帶的。「」 LP後

我怎樣才能找回它們之間的字符串的所有實例兩個標識符？

Answer 1

所以像這樣？我假設您的分隔符:和,在整個字符串中是一致的，並且使用雙引號"來包含所需的字符串。

# escape double quotes 
longstring = %q(bunchofotherstringstuffandcharacters"hisquote":"The most important aspect of the painting was the treatment of lighting.","lp":andthenalotmorestringandcharacters) 

# split on double quotes 
substrings = longstring.split("\"").to_enum 

# somewhere to sure the strings you want 
save = [] 

# use a rescue clause to detect that the enumerator 'substrings' as reached an end 
begin 
    while true do 
     remember = substrings.next 
     case substrings.peek # lets see if that next element is our deliminator 
     when ":" # Once the semicolon is spotted ahead, grab the three strings we want. 
      save << remember 
      substrings.next # skip the ":" 
      save << substrings.next 
      substrings.next # skip the "," 
      save << substrings.next 
     end 
    end 
rescue StopIteration => e 
    puts "End of Substring Enumeration was reached." 
ensure 
    puts save.inspect #=> ["hisquote", "The most important aspect of the painting was the treatment of lighting.", "lp"] 
end