Tweets從一個hashtag檢索 - forloop php

我試圖從熱門標籤在我的國家打印熱門推文。首先，我獲取了趨勢標籤，然後我在推文網址中設置查詢，以便在趨勢標籤中。Tweets從一個hashtag檢索 - forloop php

問題是，推文只從一個hashtag中獲取，而且是最不熱門的推文！此外，不知何故，鳴叫重複！

如何從熱門標籤無需重複獲取熱門推文？

這是我的代碼：

<html> 
<?php 
use Abraham\TwitterOAuth\TwitterOAuth; 

require_once('twitter-api-php-master/TwitterAPIExchange.php'); 

$settings = array(
    'consumer_key' => '', 
    'consumer_secret' => '', 

    'oauth_access_token' => '', 
    'oauth_access_token_secret' => '',); 
$Saudi_id = 23424938; 
$requestMethod = 'GET'; 
$twitter = new TwitterAPIExchange($settings); 
/* the url that have the request*/ 
$url = 'https://api.twitter.com/1.1/trends/place.json'; 
/*appending values into the url*/ 
$get_request = '?id=' . $Saudi_id ; 
$json_data = $twitter->setGetfield($get_request)->buildOauth($url, $requestMethod)->performRequest(); 
/* converting JSON format into PHP object */ 
$redeable_data = json_decode($json_data); 
/* creating the TRENDS array linked with converted object*/ 
$trends = $redeable_data[0]->trends; 
// Set here the Twitter account from where getting latest tweets 
foreach($trends as $trend){ 
     # print only the hashtags the starts with # 
     if(preg_match("/^#/i",$trend->name)){ 
     /* prining the name of each hashtag along with the url for navigation as list*/ 
     $name=$trend->name; 
    } 
    } 
// Get timeline using TwitterAPIExchange 
$url = 'https://api.twitter.com/1.1/search/tweets.json'; 
$getfield = "q=".$name."&result_type=recent&count=700"; 
$tweets = $twitter 
    ->setGetfield($getfield) 
    ->buildOauth($url, $requestMethod) 
    ->performRequest(); 

$tweets = json_decode($tweets); 
echo "<ul>"; 
if(isset($tweets->statuses) && is_array($tweets->statuses)) { 
    if(count($tweets->statuses)) { 
     foreach($tweets->statuses as $tweet) { 
      echo "<li>"; 
    echo ($tweet->text); 
    echo "</li>"; 
    // if any image were included within the tweet , print it with size 20% 
    if (isset($tweet->entities->media)) { 
    $media_url = $tweet->entities->media[0]->media_url; 
    echo "<img src='{$media_url}' width='20%' />"; 
    } 
     } 
    } 
    else { 
     echo 'The result is empty'; 
    } 
} 
echo "</ul>"; 

?> 
</html>

注意：我使用的PHP與HTML和TwitterAPIExchange.php庫

來源

2017-04-17 Al-Hanouf

沿着代碼在這個代碼

foreach($trends as $trend){ 
     # print only the hashtags the starts with # 
     if(preg_match("/^#/i",$trend->name)){ 
     /* prining the name of each hashtag along with the url for navigation as list*/ 
     $name=$trend->name; 
    } 
    }

你正在循環瀏覽大多數趨勢標籤到最少趨勢，並且只保留最後一個爲$名稱 - 因此您最終只能獲得最少的趨勢。如果你想獲得的鳴叫每個X的最流行的主題標籤做這樣的事情

$trend = reset($trends); 
$name = $trend->name;

：

for ($x = 0; $x <= 5; $x++) 
     $trend = $trends[$x] 
     # print only the hashtags the starts with # 
     if(preg_match("/^#/i",$trend->name)){ 
     /* prining the name of each hashtag along with the url for navigation as list*/ 
     $name=$trend->name; 
     /*get the tweets here inside the loop*/ 
     $url = 'https://api.twitter.com/1.1/search/tweets.json'; 
     $getfield = "q=".$name."&result_type=recent&count=700"; 
     $tweets = $twitter 
     ->setGetfield($getfield) 
     ->buildOauth($url, $requestMethod) 
     ->performRequest(); 

    $tweets = json_decode($tweets); 
    echo "<ul>"; 
    if(isset($tweets->statuses) && is_array($tweets->statuses)) { 
     if(count($tweets->statuses)) { 
     foreach($tweets->statuses as $tweet) { 
     echo "<li>"; 
    echo ($tweet->text); 
    echo "</li>"; 
    // if any image were included within the tweet , print it with size 20% 
    if (isset($tweet->entities->media)) { 
     $media_url = $tweet->entities->media[0]->media_url; 
     echo "<img src='{$media_url}' width='20%' />"; 
    } 
    } 
    } 
    else { 
    echo 'The result is empty'; 
    } 
    } 
    echo "</ul>"; 
    } 
    }

來源

2017-04-17 18:24:38

你知道如何解決搶到只有第一個，這樣做這個，請嗎？ –

如果你只想要最流行的循環，那麼只能從$ trends讀取第一個循環 - 所以不要循環（或者只循環一次） –

我添加了一些代碼 - 未經測試，因爲我還沒有完成php一段時間，但它希望是接近 –

Tweets從一個hashtag檢索 - forloop php

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