這裏我有json輸出如下。我想要做什麼是我想要範圍,生產,refreshtoken,access_token作爲獨立的PHP變量從var_dump輸出。如何將vardump輸出的值賦給php中的變量?
這裏是JSON輸出
array ('status' => 'OK', 'statusCode' => 200, 'time' => 1.628268, 'header' => array (0 => 'HTTP/1.1 200 OK Date: Fri, 06 May 2016 06:22:42 GMT Server: O2-PassThrough-HTTP Content-Type: application/json Pragma: no-cache Cache-Control: no-store Transfer-Encoding: chunked ',), 'body' => '{"scope":"TARGET","token_type":"bearer","expires_in":2324,"refresh_token":"4567f358c7b203fa6316432ab6ba814","access_token":"55667dabbf188334908b7c1cb7116d26"}',)
這裏是我的PHP
var_dump($r);
echo $var[0]."<br>";
echo $var[1]."<br>";
echo $var[2]."<br>";
echo $var[3]."<br>";
echo $var[4]."<br>";
echo $var[5]."<br>";
echo $var[6]."<br>";
echo $var[7]."<br>";
echo $var[8]."<br>";
使用json_decode($改編[ '身體'],真正); – JYoThI