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每次我提交我的網站的表單時,它只會創建一個新的ID。但是其他所有的值都是空的,我該怎麼辦?無法將文本值上傳到mysql
<?php
error_reporting(E_ALL);ini_set('display_errors',1);
$servername = "localhost";
$username = "seamaszhou";
$password = "123456";
$dbname = "guest";
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username,
$password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO guest
(guestName,guestEmail,guestContent)
VALUES (:guestName, :guestEmail, :guestContent)");
$stmt->bindParam(':guestName', $guestName);
$stmt->bindParam(':guestEmail', $guestEmail);
$stmt->bindParam(':guestContent', $guestContent);
// insert a row
$guestName = "$guestName";
$guestContent = "$guestContent";
$guestEmail = "$guestEmail";
$stmt->execute();
?>
見有關[PHP手冊字符串](http://php.net/manual/en/language.types.string.php)並閱讀「可變擴展」。 –
感謝大衛的幫助。我其實想要製作一個表單讓用戶填寫這些信息,然後提交給我的服務器。我該怎麼做?我嘗試了'$ guestContent = $ _ POST ['guestContent'];'但似乎不起作用。 –
@seamaszhou:有什麼不適合呢?這個價值是否被首先發布?顯示的代碼不包含任何HTML表單,您需要這些表單才能擁有HTML表單。 – David