（Python）的元組/列表分配

Question

目前分配我的變量，我有這樣的：

rows = [[convert[random.randint(0,7)] for _ in range(5)] for _ in range(5)] 
printedrows = [("[X]","[X]","[X]","[X]","[X]"," <- V: {} TOTAL: {}".format(row.count(0), sum(row))) for row in rows] 

這將創建5列隨機值：

('[X]', '[X]', '[X]', '[X]', '[X]', ' <- V: 1 TOTAL: 9') 
('[X]', '[X]', '[X]', '[X]', '[X]', ' <- V: 2 TOTAL: 5') 
('[X]', '[X]', '[X]', '[X]', '[X]', ' <- V: 0 TOTAL: 6') 
('[X]', '[X]', '[X]', '[X]', '[X]', ' <- V: 1 TOTAL: 10') 
('[X]', '[X]', '[X]', '[X]', '[X]', ' <- V: 0 TOTAL: 8') 

我想重新分配「X 「s的數字，所以它看起來像這樣：

('[X]', '[2]', '[X]', '[X]', '[X]', ' <- V: 1 TOTAL: 9') 
('[1]', '[X]', '[3]', '[0]', '[1]', ' <- V: 2 TOTAL: 5') 
('[X]', '[X]', '[1]', '[X]', '[X]', ' <- V: 0 TOTAL: 6') 
('[1]', '[X]', '[X]', '[X]', '[2]', ' <- V: 1 TOTAL: 10') 
('[X]', '[3]', '[X]', '[2]', '[X]', ' <- V: 0 TOTAL: 8') 

但是，當我使用此:(僅示例 - 該位置是用戶確定的）

convert = {0:0,1:1,2:2,3:3,4:0,5:1,6:2,7:1} 

printedrows[y][x] = rows[y][x] 
TypeError: 'tuple' object does not support item assignment 

有沒有什麼我可以做的，以解決這個問題，以便我可以更改沒有錯誤的值？謝謝。

Answer 1

要創建一個使用元組的列表：

printedrows = [("[X]","[X]","[X]","[X]","[X]"," <- V: {} TOTAL: {}".format(row.count(0), sum(row))) 
       for row in rows] 

您可以替代這些名單：

printedrows = [["[X]","[X]","[X]","[X]","[X]"," <- V: {} TOTAL: {}".format(row.count(0), sum(row))] 
       for row in rows] 

注意的方括號而不是在圓括號那裏。