計算字符串中的字數量php

Question

我正在打印包含來自給定url的HTML內容的字符串。我想要做的是找出字符串中有多少個單詞以及它們出現的次數。

例如：

今天| 1

如何| 1

你好| 1

代碼：

$string = "Hello how are you today" 

Answer 1

把你的$ cResult作爲輸入：

$word_counts = []; 

// remove scripts and styles completely, then strip tags 
$cResult = preg_replace('#<script(.*?)>(.*?)</script>#is', '', $cResult); 
$cResult = preg_replace('#<style(.*?)>(.*?)</style>#is', '', $cResult); 
$cResult = strip_tags($cResult); 

// strip all characters that are not letters: 
$word_array_raw = explode(' ',preg_replace('/[^A-Za-z ]/', ' ', $cResult)); 

// loop through array: 
foreach ($word_array_raw as $word) { 
    $word = trim($word); 
    if($word) { 
     isset($word_counts[$word]) ? $word_counts[$word]++ : $word_counts[$word] = 1; 
    } 
} 

// Array with all stats sorted in descending order: 
arsort($word_counts); 

// Output format you wanted: 
foreach ($word_counts as $word=>$count) { 
    echo "$word | $count<br>"; 
} 

希望它可以幫助

Answer 2

事情是這樣的：

$s = "lorem ipsum dolor sit amet, consectetur adipiscing elit, sit sed do lorem eiusmod tempor"; 
    $w = preg_split('=[^\w]=', $s, NULL, PREG_SPLIT_NO_EMPTY); 
    $words = []; 

    foreach ($w as $word) { 
    if (!isset($words[$word])) $words[$word] = 0; 
    $words[$word]++; 
    } 
    print_r($words); 

輸出：

Array 
(
    [lorem] => 2 
    [ipsum] => 1 
    [dolor] => 1 
    [sit] => 2 
    [amet] => 1 
    [consectetur] => 1 
    [adipiscing] => 1 
    [elit] => 1 
    [sed] => 1 
    [do] => 1 
    [eiusmod] => 1 
    [tempor] => 1 
) 

這就是你想要的？