打破for循環使用，如果從單一的線路條件爲多行

Question

我真的與這部分代碼混淆：

newip = [] 
c = Counter() 
for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]): 
    for entry in group: 
     c.update(re.findall(r'[0-9]+(?:\.[0-9]+){3}', entry)) 
    newip.extend(ip for ip, cnt in c.items() if cnt > 10) 

如何突破這兩條線爲多行，一邊做同樣的任務？

for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]): 
... 
    newip.extend(ip for ip, cnt in c.items() if cnt > 10) 

日誌文件：

12/30-04:09:41.070967 [**] [1:10000001:1] snort alert [1:0000001] [**] [classification ID: 0] [Priority ID: 0] {ICMP} 192.168.232.2:41676 -> 192.168.248.2:21 
12/30-04:09:41.070967 [**] [1:10000001:1] snort alert [1:0000001] [**] [classification ID: 0] [Priority ID: 0] {ICMP} 192.168.232.2:41673 -> 192.168.248.2:21 

現在，我有兩個問題：

1. 請解釋一下這兩條線正好做。
2. 如何將它們分成多行，同時承擔相同的任務？

感謝和問候。

Answer 1

線

newip.extend(ip for ip, cnt in c.items() if cnt > 10) 

確實

for ip, cnt in c.items() 
    if cnt > 10: 
     #newip.extend([ip]) # with [ ] 
     newip.append(ip) # without [ ] 

---

線

for key, group in groupby(logfile, key=lambda e: e.split('.',1)[0]): 

做（但可能groupby創建的元組(key, group)的名單，我使用詞典]）

groups = groupby(logfile, key=lambda e: e.split('.',1)[0]) 

for key, group in groups.items(): 

，這我會猜

groups = dict() 

for element in logfile: 
    key = element.split('.',1)[0] 
    if key not in groups: 
     groups[key] = [] 
    groups[key].append(element) 

for key, group in groups.items():