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我目前正在嘗試使用常規Ksoap實現從我的webservice檢索數組。但是,試圖訪問該數組時,我收到以下錯誤logcat中:kSoap2 Android - Cast Class Exception(SoapObject)
04-27 00:27:01.772: ERROR/AndroidRuntime(530): Caused by: java.lang.RuntimeException: Unable to
start activity ComponentInfo{android.waiter/android.waiter.TablesActivity}:
java.lang.ClassCastException: org.ksoap2.serialization.SoapPrimitive
看來,由於某種原因,肥皂沒有與我鑄造我的屬性值的方式相處。附件是問題的代碼(和相關方法)
public static TableDTO[] RetrieveFromSoap(SoapObject soap)
{
TableDTO[] tables = new TableDTO[soap.getPropertyCount()];
for (int i = 0; i < tables.length-1; i++) {
SoapObject pii = (SoapObject) soap.getProperty(i);
TableDTO table = new TableDTO();
table.setTableID(Integer.parseInt(pii.getProperty(0).toString()));
table.setCapacity(Integer.parseInt(pii.getProperty(1).toString()));
table.setStatusFlag(pii.getProperty(2).toString());
table.setCurrentWaiter(pii.getProperty(3).toString());
tables[i] = table;
}
return tables;
}
TableDTO信息:
@Override
public Object getProperty(int arg0) {
switch(arg0)
{
case 0:
return TableID;
case 1:
return Capacity;
case 2:
return StatusFlag;
case 3:
return currentWaiter;
}
return null;
}
@Override
public int getPropertyCount() {
// TODO Auto-generated method stub
return 3;
}
@Override
public void getPropertyInfo(int arg0, Hashtable arg1, PropertyInfo info) {
switch(arg0){
case 0:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "TableID";
break;
case 1:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "Capacity";
break;
case 2:
info.type = PropertyInfo.STRING_CLASS;
info.name = "StatusFlag";
break;
case 3:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "currentWaiter";
break;
default:break;
}
}
@Override
public void setProperty(int arg0, Object value) {
switch(arg0)
{
case 0:
TableID = Integer.parseInt(value.toString());
break;
case 1:
Capacity = Integer.parseInt(value.toString());
break;
case 2:
StatusFlag = value.toString();
break;
case 3:
currentWaiter = value.toString();
break;
default :
break;
}
}
問題是與
SoapObject pii = (SoapObject) soap.getProperty(i);
它不喜歡鑄造有行。我對如何解決這個問題感到茫然。
感謝您的時間和幫助!
偉大的答案,快速,簡單,並解決了我的問題。謝謝您的幫助! – BPuryear 2011-04-27 15:59:13