創建幫助所需的SQL查詢

Question

我在我的數據庫中有3個表格，我需要查詢，其結果是Tweet，用戶的暱稱，誰寫了這條推文和pubdate.But我只需要那些我關注的人的推文。在111212_follow表中，我們可以看到follower_id，這是誰在追蹤，我只需要追蹤follower_id後面的人的結果（followed_id）。 Follower_id和followed_id是來自111212_users表的用戶的ID。謝謝大家的幫助。

我有1個工作查詢的例子，我不知道如何在我的情況下使用它。

"SELECT tweet_id, poster_id, t112586_users.username as poster, tweet_message, post_date, t112586_users.pics FROM t112586_tweets 
      INNER JOIN t112586_users ON t112586_tweets.poster_id = t112586_users.user_id 
      WHERE poster_id IN(SELECT followee FROM t112586_followers where follower = $id) 
      ORDER BY post_date DESC;" 

更新： 我有工作的查詢，但是這一次不給我的暱稱和pubdate的。 $userId我脫離盤中回吐，這個變量讓我們知道用戶ID，因爲我們在

登錄

"SELECT 111212_tweets.user_id, 111212_tweets.text FROM 111212_tweets INNER JOIN 111212_follow ON 111212_tweets.user_id=111212_follow.followed WHERE 111212_follow.follower='$userId'" 


    --------------------------------------- 
    111212_follow 
    ---------------------------------------  
    follow_id | followed_id | follower_id | 
    --------------------------------------- 
     3  |  2  |  7  | 
    --------------------------------------- 
     5  |  1  |  7  | 
    --------------------------------------- 

    --------------------------------------------- 
    111212_tweets 
    ---------------------------------------------  
     id  | user_id | tweet | pubdate | 
    --------------------------------------------- 
     3   | 2  | text | date | 
    --------------------------------------------- 
     4   | 1  | text | date | 
    --------------------------------------------- 
     5   | 1  | text | date | 
    --------------------------------------------- 

    ---------------------------------------------------------------------------- 
    111212_users 
    ---------------------------------------------------------------------------- 
     id  | name   | nickname | email | password 
    ---------------------------------------------------------------------------- 
     1   | Sten   |  user1  | t1@t.com | 123123 
    ---------------------------------------------------------------------------- 
     2   | Mark   |  user2  | t2@t.com | 123123 
    ---------------------------------------------------------------------------- 
     7   | John   |  user3  | t3@t.com | 123123 
    ---------------------------------------------------------------------------- 

UPDATE：

<ul id="tweetDisplay"> 
      <p>Tweets: </p> 
      <?php 
      $userId = $_SESSION['userId']; 
      $query = "SELECT T1.`tweet`, T2.`nickname`,T1.`pubdate`FROM `111212_tweets` T1 LEFT JOIN `111212_users` T2 ON T1.`user_id` = T2.`id` LEFT JOIN `111212_follow` T3 ON T1.`user_id` = T3.`followed_id` WHERE T3.`follower_id` = '$userId'"; 
      $searchQuery = mysql_query($query); 
      while($row = mysql_fetch_array($searchQuery)){ 
      echo "----------------------------------------------"; 
      echo "<li>Nickname: ".$row['nickname']."</li><li>".$row['text']."</li><li class='date'>".$row['pubdate']."</li>"; 
      } 
      ?> 
     </ul> 
    </div> 

Answer 1

嘗試此查詢，與用戶的你」的ID替換YOUR_ID重新登錄：

SELECT 
    T1.`tweet`, 
    T2.`nickname`, 
    T1.`pubdate` 
FROM `111212_tweets` T1 
LEFT JOIN `111212_users` T2 
ON T1.`user_id` = T2.`id` 
LEFT JOIN `111212_follow` T3 
ON T1.`user_id` = T3.`followed_id` 
WHERE T3.`follower_id` = 'YOUR_ID'