c＃上傳文件到流？

Question

我希望用戶上傳文件並將其保存到流中。

這是迄今爲止代碼：

private void Submit_ServerClick(object sender, System.EventArgs e) 
     { 


       fn = System.IO.Path.GetFileName(File1.PostedFile.FileName); 

     } 

Answer 1

你可以做這樣的

string filePath = uploadFile(fileUploadControl.FileContent); 

private string uploadFile(Stream serverFileStream) 
{ 
    string filename = ConfigurationManager.AppSettings["FileUploadTempDir"] + 
    DateTime.Now.ToString("yyyyMMddhhmm") + "_" + 
    Customer.GetCustomerName(CustomerId).Replace(" ", "_") + ".txt"; 

    try 
    { 
    int length = 256; 
    int bytesRead = 0; 
    Byte[] buffer = new Byte[length]; 

    // write the required bytes 
    using (FileStream fs = new FileStream(filename, FileMode.Create)) 
    { 
     do 
     { 
      bytesRead = serverFileStream.Read(buffer, 0, length); 
      fs.Write(buffer, 0, bytesRead); 
     } 
     while (bytesRead == length); 
    } 

    serverFileStream.Dispose(); 
    return filename; 
    } 
    catch (Exception ex) 
    { 
    lblErrorMessage.Text += "An unexpeded error occured uploading the file. " + ex.Message; 
    return string.Empty; 
    } 
} 

我希望它會幫助你...

Answer 2

的對象FileUpload.PostedFile回報有InputStream property可以讀取上傳的文件數據。

Answer 3

看起來這一個http://support.microsoft.com/kb/323246

string fn = System.IO.Path.GetFileName(File1.PostedFile.FileName); 
string SaveLocation = Server.MapPath("Data") + "\\" + fn; 
try 
{ 
    File1.PostedFile.SaveAs(SaveLocation); 
    Response.Write("The file has been uploaded."); 
} 
catch (Exception ex) 
{ 
    Response.Write("Error: " + ex.Message); 
    //Note: Exception.Message returns a detailed message that describes the current exception. 
    //For security reasons, we do not recommend that you return Exception.Message to end users in 
    //production environments. It would be better to put a generic error message. 
}