當連續輸入錯誤時，循環中斷java

當您連續兩次輸入一個'i'等隨機值時，程序終止。我想這樣做，所以「無效的數據請再試一次」，然後「你想再玩一次」繼續重複，直到輸入N或Y.當連續輸入錯誤時，循環中斷java

7 8 5 
No numbers match 
Do you want to play again? 
i 
Invalid data please try again 
Do you want to play again? 
i 
Thank you for using this program

它應該是：

7 8 5 
No numbers match 
Do you want to play again? 
i 
Invalid data please try again 
Do you want to play again? 
i 
Invalid data please try again 
Do you want to play again?

...等等。

代碼：

import java.util.Random; 
import java.util.Scanner; 

public class TestSlotMachine { 

    public static void main(String[] args) { 
     String choice; 

     Scanner keyboardScanner = new Scanner(System.in); 

     do { 
      Random randomNumber = new Random(); 
      int slot1, slot2, slot3; 

      slot1 = randomNumber.nextInt(9); 
      slot2 = randomNumber.nextInt(9); 
      slot3 = randomNumber.nextInt(9); 

      System.out.println(slot1+" "+slot2+" "+ slot3); 

      if (slot1 != slot2 && slot1 != slot3 && slot2 != slot3) { 
       System.out.println("No numbers match"); 
      } 
      else if (slot1 == slot2 && slot2 == slot3) { 
       System.out.println("Three numbers match"); 
      } 
      else { 
       System.out.println("Two numbers match"); 
      } 

      System.out.println("Do you want to play again?"); 
      choice = keyboardScanner.next(); 
      if (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y")) { 
       System.out.println("Invalid data please try again"); 
       System.out.println("Do you want to play again?"); 
       choice = keyboardScanner.next(); 
      } 

     } while (choice.equalsIgnoreCase("y")); 

     System.out.println("Thank you for using this program"); 
     keyboardScanner.close(); 
    } 
}

來源

2015-01-12 Adam

if (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))

可以成爲

while (!choice.equalsIgnoreCase("n") && !choice.equalsIgnoreCase("y"))

來源

2015-01-12 10:36:29

它不應該是||代替＆＆？ –

@CodingEnthusiast不，因爲那樣會永遠是真的。 – Kayaman

哦，我的壞。剛剛意識到。謝謝 –

當連續輸入錯誤時，循環中斷java

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