1
IM試圖使類別和子類別,即時檢查this models ,但我有此錯誤:Django的分類與子分類和網址
Truncated incorrect DOUBLE value: 'nacionales'
其中「nacionales」是父類的,我知道,我的問題也許是在urls.py,但真正的,我不知道如何設置URL的這種情況下...
我model.py:
# from ...
class Categoria(models.Model):
titulo = models.CharField(max_length=75, unique=True)
slug = models.SlugField(max_length=200,unique=True)
parent = models.ForeignKey('self', blank=True, null=True, related_name='child')
# functions....
我views.py:
# from ...
def noticias_categoria(request,parent_id,child):
categoria = get_object_or_404(Categoria,parent=parent_id,slug=child)
return object_list(request, queryset=categoria.noticia_set.all(), paginate_by=20,
template_name='categorias/categoria_list.html',
extra_context={'categoria':categoria})
我的類別urls.py:
# from ...
url(r'^(?P<parent_id>[-\w]+)/(?P<child>[-\w]+)/$',
noticias_categoria,
name='noticia_detail'
),
我url.py:
(r'^categorias/', include('categorias.urls')),
謝謝你們
你能提供的請求(URL)? – Fragsworth 2009-09-13 21:22:10