我試圖存儲值結構像這樣的數組:如何值存儲在陣列,然後用它作爲JSON
{"parent":
{"class":"Green","user_name":"Nitish","user_loc":"Delhi","user_id":1,"user_blockclass":null,
"child":[
{"class":"Green","user_name":null,"user_loc":null,"user_id":1,"user_blockclass":"fst",
"child":[
{"class":"Green","user_name":"pandey","user_loc":"sdgfsjd","user_id":6,"user_blockclass":"fst"},
{"class":"Green","user_name":"chaku","user_loc":"sdgjs","user_id":7,"user_blockclass":"snd"},
{"class":"Green","user_name":"iks","user_loc":"sjkdfhkjs","user_id":8,"user_blockclass":"trd"},
{"class":"Green","user_name":"yash","user_loc":"hfksjdhfk","user_id":9,"user_blockclass":"frt"},
{"class":"Green","user_name":"joshi","user_loc":"dsfh","user_id":10,"user_blockclass":"fth"}
]},
{"class":"Green","user_name":null,"user_loc":null,"user_id":1,"user_blockclass":"snd",
"child":[
{"class":"Green","user_name":"pandey","user_loc":"sdgfsjd","user_id":6,"user_blockclass":"fst"},
{"class":"Green","user_name":"chaku","user_loc":"sdgjs","user_id":7,"user_blockclass":"snd"},
{"class":"Green","user_name":"iks","user_loc":"sjkdfhkjs","user_id":8,"user_blockclass":"trd"},
{"class":"Green","user_name":"yash","user_loc":"hfksjdhfk","user_id":9,"user_blockclass":"frt"},
{"class":"Green","user_name":"joshi","user_loc":"dsfh","user_id":10,"user_blockclass":"fth"}
]},
]
}
}
我試圖把這個在兩個不同數組和加入它們,但它沒有得到approrpiate結果,我使用了一個迭代來存儲不同值的變量,如果我不使用迭代它會重疊值並且只顯示最後存儲的值。以下是我的代碼:
$blockclass = ['fst', 'snd', 'trd', 'frt', 'fth'];
$i = 0;
$children = $user->relations()->wherePlanId($selectplan)->get();
foreach($children as $ch)
{
$j = 0;
$subuserinfo = [];
$parent_id = $ch->pivot->child;
$subuser = User::find($ch->pivot->child);
$subuserinfo['class'] = "Green";
$subuserinfo['user_name'] = $ch->name;
$subuserinfo['user_loc'] = $ch->city;
$subuserinfo['user_id'] = $ch->id;
$subuserinfo['user_blockclass'] = $blockclass[$i];
if($subuser){
$subchildren = $subuser->relations()->wherePlanId($selectplan)->get();
foreach($subchildren as $subchild)
{
$subsubuser = User::find($subchild->pivot->child);
$subsubuserinfo['class'] = "Green";
$subsubuserinfo['user_name'] = $subsubuser->name;
$subsubuserinfo['user_loc'] = $subsubuser->city;
$subsubuserinfo['user_id'] = $subsubuser->id;
$subsubuserinfo['user_blockclass'] = $blockclass[$j];
$subuserinfo['child'][$i][$j++] = $subsubuserinfo;
}
}
else
{
$subuserinfo['child'][$i][$j++] = NULL;
}
$userinfo['child'][$i++] = $subuserinfo;
}
$tree = $userinfo;
dd($tree);
目前這我得到的數據結構是採用以下格式:
array:6 [▼
"class" => "Green"
"user_name" => "Nitish"
"user_loc" => "Delhi"
"user_id" => 1
"user_blockclass" => null
"child" => array:4 [▼
0 => array:6 [▼
"class" => "Green"
"user_name" => null
"user_loc" => null
"user_id" => 1
"user_blockclass" => "fst"
"child" => array:1 [▼
0 => array:5 [▼
0 => array:5 [▼
"class" => "Green"
"user_name" => "pandey"
"user_loc" => "sdgfsjd"
"user_id" => 6
"user_blockclass" => "fst"
]
1 => array:5 [▼
"class" => "Green"
"user_name" => "chaku"
"user_loc" => "sdgjs"
"user_id" => 7
"user_blockclass" => "snd"
]
2 => array:5 [▼
"class" => "Green"
"user_name" => "iks"
"user_loc" => "sjkdfhkjs"
"user_id" => 8
"user_blockclass" => "trd"
]
]
]
]
1 => array:6 [▶]
2 => array:6 [▶]
3 => array:6 [▶]
我不能這樣我以後在這個格式來獲取數據,也希望將數據作爲json格式使用。幫幫我。
我面臨的困難與數據格式不來適當的。 –
你能打印出你當前的JSON數據格式和你想要的JSON數據格式嗎? –
它已經在問題的開始,我正在尋找的json格式,最後陣列格式是我得到的值。 –