從數據庫查詢嵌套關聯數組問題

Question

嗨我想查詢最終結果應該看起來像這個json數組下面的關聯數組。然而，我希望數據部分和id名稱部分查詢一次爲每個節點和毗鄰部分多次查詢，如果一個節點有多個鄰接，如果條件是多少，我怎麼查詢此嵌套數組的一部分在保持這種結構的同時，其餘的一次都完成了，但是有多個節點或沒有鄰接節點？

var json =[{ 
     "adjacencies": [{ 
      "nodeTo": "graphnode9", 
      "nodeFrom": "graphnode5", 
      "data": {} 
     }], 
     "data": { 
      "$color": "#C74243", 
      "$type": "triangle", 
     }, 
     "id": "graphnode5", 
     "name": "graphnode5" 
    }]; 

這裏是我的數據庫結構

nodes     Relationships      
-----     ------------- 
id int(11),   id int(11), 
name varchar(35),  to int(11), //this is the destination node from the id relation 
color varchar(7),  data varchar(0) null 
type varchar (12), Foreign key (id) references nodes(id) 
Primary key (id)  

engine = innodb  

這是我在得到一個關聯數組的嘗試，但它查詢一次全部和複製整個strucute。

function getjson(){ 
    $db = adodbConnect(); 
    $query = "SELECT nodes.*, relationships.* FROM nodes inner JOIN relationships ON nodes.id = relationships.id"; 
    $result = $db -> Execute($query); 

    while($row=$result->FetchRow()) { 
     $id = (float)$row['id']; 
     $name = $row['name']; 
     $color1 = $row['color']; 
     $type1 = $row['type']; 
     $to = (float)$row['to']; 

     $array = array(
      "adjacencies:" => array(
       "nodeTo" => "$to", 
       "nodeFrom" => "$id", 
       "data" => array() 
      ), 
      "data" => array(
       "$"."color" => $color1, 
       "$"."type" => $type1 
      ), 
      "id".":" => $id, 
      "name".":" => $name 
     ); 

    } 
    print"$array"; 
    json_encode($array); 
} 

Answer 1

你需要在循環外部創建數組和添加項目

$array = array(); 
while($row=$result->FetchRow()) { 
    $array[] = array(
     "adjacencies:" => array(
      "nodeTo" => (float)$row['to'], 
      "nodeFrom" => (float)$row['id'], 
      "data" => array() 
     ), 
     "data" => array(
      '$color' => $row['color'], 
      '$type' => $row['type'] 
     ), 
     "id" => (float)$row['id'], 
     "name" => $row['name'] 
    ); 

}