我正在使用Java 6和spring-ws創建一個非常簡單的web服務,它以BusquedaRequest Jaxb對象的形式接收2個參數並返回相同的對象。spring使用帶註釋的端點時找不到適配器
該對象已使用xjc編譯器創建,我使用Jaxb2Marshaller作爲mashaller,GenericMarshallingMethodEndpointAdapter將其轉換爲傳入的xml並轉出。當擴展AbstractMarshallingPayloadEndpoint類時,我有這個工作,但當我切換到使用Endpoint和有效內容註釋時,它總是失敗。
Web服務啓動正常,但當用客戶端點擊它時,我收到此異常。
java.lang.IllegalStateException: No adapter for endpoint [public package.busqueda.ws.BusquedaRequest package.busqueda.ws.BusquedaEndpoint.getResultas(package.busqueda.ws.BusquedaRequest)]: Does your endpoint implement a supported interface like MessageHandler or PayloadEndpoint?
at org.springframework.ws.server.MessageDispatcher.getEndpointAdapter(MessageDispatcher.java:286)
at org.springframework.ws.server.MessageDispatcher.dispatch(MessageDispatcher.java:227)
at org.springframework.ws.server.MessageDispatcher.receive(MessageDispatcher.java:170)
at org.springframework.ws.transport.support.WebServiceMessageReceiverObjectSupport.handleConnection(WebServiceMessageReceiverObjectSupport.java:88)
at org.springframework.ws.transport.http.WebServiceMessageReceiverHandlerAdapter.handle(WebServiceMessageReceiverHandlerAdapter.java:57)
at org.springframework.ws.transport.http.MessageDispatcherServlet.doService(MessageDispatcherServlet.java:230)
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644)
at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:560)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Thread.java:662)
我見過這個問題的答案,它表明使用我已經完成的xjc編譯器編譯對象。還有一些建議認爲Adapter沒有在spring-ws-servlet.xml中定義,我也這樣做過。看到彈簧WS-servlet.xml中定義如下:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">
<bean id="busquedaEndpoint" class="package.BusquedaEndpoint" />
<bean class="org.springframework.ws.server.endpoint.adapter.GenericMarshallingMethodEndpointAdapter">
<constructor-arg ref="marshaller"/>
</bean>
<bean id="marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller">
<property name="classesToBeBound">
<list>
<value>package.BusquedaRequest</value>
</list>
</property>
</bean>
<bean id="busqueda"
class="org.springframework.ws.wsdl.wsdl11.DefaultWsdl11Definition">
<property name="schema" ref="schema" />
<property name="portTypeName" value="Busqueda" />
<property name="locationUri" value="/BusquedaService/" />
</bean>
<bean id="schema" class="org.springframework.xml.xsd.SimpleXsdSchema">
<property name="xsd" value="/WEB-INF/busqueda.xsd" />
</bean>
<bean class="org.springframework.ws.server.endpoint.mapping.PayloadRootAnnotationMethodEndpointMapping"/>
</beans>
類端點如下:
package package.busqueda.ws;
import org.springframework.ws.server.endpoint.annotation.Endpoint;
import org.springframework.ws.server.endpoint.annotation.PayloadRoot;
@Endpoint
public class BusquedaEndpoint {
@PayloadRoot(localPart = "BusquedaRequest", namespace = "http://busqueda/schemas")
public BusquedaRequest getResultas(BusquedaRequest aRequest) {
return aRequest;
}
}
我產生的BusqeudaRequest目的是如下的xsd:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
elementFormDefault="qualified"
attributeFormDefault="qualified"
xmlns="http://busqueda/schemas"
targetNamespace="http://busqueda/schemas">
<xs:element name="BusquedaRequest">
<xs:complexType>
<xs:all>
<xs:element name="Consulta" type="xs:string" />
<xs:element name="Permisos" type="xs:string" />
</xs:all>
</xs:complexType>
</xs:element>
</xs:schema>
任何人都有任何想法延伸我已經實施的建議?
您確定要返回`BusquedaRequest`嗎? – 2010-12-22 18:08:37
有趣的是,我使用它,並通過縮進例外的第一行和xmls 4空格,它似乎編纂了一大堆。然而,我無法複製這種行爲,所以我認爲這是我做的事情,爲此我表示歉意,儘快在我意識到這種情況時嘗試編輯,但您首先到達那裏。 Thankyou修復 – zode64 2010-12-22 18:08:50
@ org.life.java,這是一種簡化的方式,所以我只使用一個jaxb對象,最初我使用了多個。我承認這可能會讓事情有點混亂。 – zode64 2010-12-22 18:09:52