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如何在PHP中重複顯示ID號然後在列表中顯示?如何在使用PHP的列表中顯示
這是我在查看
<ul class="dropdown-menu" role="menu">
<li><a href="#"><?php echo ?></a></li>
</ul>
在控制器
$query=$this->mdl_mainmenu->notif_items();
$data['notifs'] = $query;
$this->load->view('vw_main_menu',$data);
在型號
function notif_items(){
$user = $this->session->userdata("username");
$this->csbrms->select("deleted_user_request.sdp_no,
deleted_user_request.approval_status");
$this->csbrms->from('deleted_user_request');
$this->csbrms->join('m_employee_masters', 'm_employee_masters.emp_no = user_request.emp_no');
$this->csbrms->where('deleted_user_request.created_by',$user);
$this->csbrms->where('deleted_user_request.approval_status' , 'Closed');
$this->csbrms->where('deleted_user_request.approval_status' , 'Resolved');
$query = $this->csbrms->get();
return $query->result();
}
'
\t <?的PHP的foreach($數據[ 'notifs']爲$ DAT){?> \t \t \t
'。因爲我們不知道它的結構是什麼,它看起來像 –對不起,它是'$ vw_main_menu ['notifs']'而不是'$ data' –