XSLT格式化輸出完成90％

Question

我想處理一些XML進行改革，使該輸入，但是我得到的問題，下面可以更好地說明：

INPUT

<?xml version="1.0" encoding="UTF8"?> 
<doc:ZINITIALIZE_FILTERS.Response xmlns:doc="urn:sapcom:document:sap:rfc:functions"> 
    <MESSAGE>Success</MESSAGE> 
    <STATUS>0</STATUS> 
    <COLLECTION> 
     <item> 
      <COLLECTION>A1</COLLECTION> 
      <SEASON>S09</SEASON> 
      <TEXT>Spring Market A1</TEXT> 
     </item> 
     <item> 
      <COLLECTION>A1</COLLECTION> 
      <SEASON>S10</SEASON> 
      <TEXT>Spring Market A1</TEXT> 
     </item> 
    </COLLECTION> 
</doc:ZINITIALIZE_FILTERS.Response> 

所需的輸出：

<?xml version="1.0" encoding="UTF8"?> 
<doc:ZINITIALIZE_FILTERS.Response xmlns:doc="urn:sapcom:document:sap:rfc:functions"> 
    <MESSAGE>Success</MESSAGE> 
    <STATUS>0</STATUS> 
    <COLLECTION> 
     <item> 
      <COLLECTION>A1</COLLECTION> 
      <SEASON>S09,S10</SEASON> 
      <TEXT>Spring Market A1</TEXT> 
     </item> 
    </COLLECTION> 
</doc:ZINITIALIZE_FILTERS.Response> 

XSLT被使用：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> 
    <xsl:output method="xml" indent="yes"/> 

    <xsl:key name="k" match="item" use="COLLECTION"/> 

    <xsl:template match="/ZINITIALIZE_FILTERS.Response"> 
     <xsl:copy> 
      <COLLECTIONS> 
       <xsl:apply-templates select="COLLECTION/item[generate-id() = 
        generate-id(key('k', COLLECTION))]"/> 
      </COLLECTIONS> 
     </xsl:copy> 
    </xsl:template> 

    <xsl:template match="COLLECTION/item"> 
     <xsl:copy> 
      <xsl:copy-of select="COLLECTION"/> 
      <SEASON> 
       <xsl:for-each select="key('k', COLLECTION)"> 
        <xsl:value-of select="SEASON"/> 

        <xsl:if test="position() != last()"> 
         <xsl:text>,</xsl:text> 
        </xsl:if> 
       </xsl:for-each> 
      </SEASON> 
      <xsl:copy-of select="TEXT"/> 
     </xsl:copy> 
    </xsl:template> 
</xsl:stylesheet> 

電流不正確的輸出：

<?xml version="1.0" encoding="UTF-8"?> 
    <ZINITIALIZE_FILTERS.Response xmlns=""><?xml version="1.0"?> 
    Success0<item xmlns:doc="urn:sap-com:document:sap:rfc:functions"><COLLECTION>A1</COLLECTION><SEASON>S09,S10,S12</SEASON><TEXT>Spring Market A1</TEXT></item> 
    </ZINITIALIZE_FILTERS.Response> 

誰能幫助？

Answer 1

用途：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> 
    <xsl:output method="xml" indent="yes"/> 
    <xsl:strip-space elements="*"/> 

    <xsl:key name="k" match="item" use="COLLECTION"/> 

    <xsl:template match="item[generate-id() = generate-id(key('k', COLLECTION))]"> 
     <xsl:copy> 
      <xsl:copy-of select="COLLECTION"/> 
      <SEASON> 
       <xsl:for-each select="key('k', COLLECTION)"> 
        <xsl:value-of select="SEASON"/> 

        <xsl:if test="position() != last()"> 
         <xsl:text>,</xsl:text> 
        </xsl:if> 
       </xsl:for-each> 
      </SEASON> 
      <xsl:copy-of select="TEXT"/> 
     </xsl:copy> 
    </xsl:template> 

    <xsl:template match="item"/> 

    <xsl:template match="@* | node()"> 
     <xsl:copy> 
      <xsl:apply-templates select="@* | node()"/> 
     </xsl:copy> 
    </xsl:template> 

</xsl:stylesheet> 

當應用到這個XML：

<doc:ZINITIALIZE_FILTERS.Response xmlns:doc="urn:sapcom:document:sap:rfc:functions"> 
    <MESSAGE>Success</MESSAGE> 
    <STATUS>0</STATUS> 
    <COLLECTION> 
     <item> 
      <COLLECTION>A1</COLLECTION> 
      <SEASON>S09</SEASON> 
      <TEXT>Spring Market A1</TEXT> 
     </item> 
     <item> 
      <COLLECTION>A1</COLLECTION> 
      <SEASON>S10</SEASON> 
      <TEXT>Spring Market A1</TEXT> 
     </item> 
    </COLLECTION> 
</doc:ZINITIALIZE_FILTERS.Response> 

它產生想要的正確結果：

<doc:ZINITIALIZE_FILTERS.Response xmlns:doc="urn:sapcom:document:sap:rfc:functions"> 
    <MESSAGE>Success</MESSAGE> 
    <STATUS>0</STATUS> 
    <COLLECTION> 
    <item> 
     <COLLECTION>A1</COLLECTION> 
     <SEASON>S09,S10</SEASON> 
     <TEXT>Spring Market A1</TEXT> 
    </item> 
    </COLLECTION> 
</doc:ZINITIALIZE_FILTERS.Response>