你好,我想獲得精確的位置,這樣我已經使用下面的鏈接致命異常:定時器0
What is the simplest and most robust way to get the user's current location in Android?
下面是從該網站的代碼:
LocationResult locationResult = new LocationResult(){
@Override
public void gotLocation(Location location){
//Got the location!
}
};
MyLocation myLocation = new MyLocation();
myLocation.getLocation(this, locationResult);
現在LocationResult
我修改了它,並希望顯示LOCATION的文本視圖 ,所以我寫下面的代碼
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LocationResult locationResult = new LocationResult(){
@Override
public void gotLocation(Location location){
TextView txtValue = (TextView)findViewById(R.id.txtValue);
txtValue.setText("LATITUDE : - "+location.getLatitude()+"\n\n LONGITUDE :- "+location.getLongitude()+"\n\n ALTITUDE :- "+location.getAltitude());
}
};
myLocation = new MyLocation();
myLocation.getLocation(this, locationResult);
}
但在我得到像
下面的例外是我的logcat
10-04 17:06:35.699: E/AndroidRuntime(5733): FATAL EXCEPTION: Timer-0
10-04 17:06:35.699: E/AndroidRuntime(5733): java.lang.NullPointerException
10-04 17:06:35.699: E/AndroidRuntime(5733): at com.example.gps_accurate_data.MainActivity$1.gotLocation(MainActivity.java:22)
10-04 17:06:35.699: E/AndroidRuntime(5733): at com.example.gps_accurate_data.MyLocation$GetLastLocation.run(MyLocation.java:119)
10-04 17:06:35.699: E/AndroidRuntime(5733): at java.util.Timer$TimerImpl.run(Timer.java:284)
不,這不是一個問題! –
你在MainActivity的第22行有什麼? – Carnal
txtValue.setText(「LATITUDE: - 」+ location.getLatitude()+「\ n \ n LONGITUDE: - 」+ location.getLongitude()+「\ n \ n ALTITUDE: - 」+ location.getAltitude()); –