如何包含JavaScript代碼以便通過w3c驗證程序？

Question

我在這裏用下面的JavaScript代碼有問題。當我的文檔中包含此JavaScript代碼時，我無法傳遞w3 xhtml驗證器。

錯誤輸出：

Error Line 224, Column 77: document type does not allow element "span" here 
    '<span onclick="' + pagerName + '.prev();" class="pg-normal"> ?Prev </span> '; 
Error Line 228, Column 27: character "'" is not allowed in the value of attribute "id" 
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam… 
Error Line 228, Column 28: value of attribute "id" must be a single token 
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam… 
Error Line 228, Column 29: character "+" is not allowed in the value of attribute "id" 
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam… 
Error Line 243, Column 43: there is no attribute "align" 
    <table id="tablepaging" class="yui" align="center"> 

JavaScript代碼如下

<script type="text/javascript"> 

function Pager(tableName, itemsPerPage) { 

this.tableName = tableName; 

this.itemsPerPage = itemsPerPage; 

this.currentPage = 1; 

this.pages = 0; 

this.inited = false; 

this.showRecords = function(from, to) { 

var rows = document.getElementById(tableName).rows; 

// i starts from 1 to skip table header row 

for (var i = 1; i > rows.length; i++) { 

if (i < from || i > to) 

rows[i].style.display = 'none'; 

else 

rows[i].style.display = ''; 

} 

} 

this.showPage = function(pageNumber) { 

if (! this.inited) { 

alert("not inited"); 

return; 

} 

var oldPageAnchor = document.getElementById('pg'+this.currentPage); 

oldPageAnchor.className = 'pg-normal'; 

this.currentPage = pageNumber; 

var newPageAnchor = document.getElementById('pg'+this.currentPage); 

newPageAnchor.className = 'pg-selected'; 

var from = (pageNumber - 1) * itemsPerPage + 1; 

var to = from + itemsPerPage - 1; 

this.showRecords(from, to); 

} 

this.prev = function() { 

if (this.currentPage > 1) 

this.showPage(this.currentPage - 1); 

} 

this.next = function() { 

if (this.currentPage < this.pages) { 

this.showPage(this.currentPage + 1); 

} 

} 

this.init = function() { 

var rows = document.getElementById(tableName).rows; 

var records = (rows.length - 1); 

this.pages = Math.ceil(records/itemsPerPage); 

this.inited = true; 

} 

this.showPageNav = function(pagerName, positionId) { 

if (! this.inited) { 

alert("not inited"); 

return; 

} 

var element = document.getElementById(positionId); 

var pagerHtml = '<span onclick="' + pagerName + '.prev();" class="pg-normal"> ?Prev </span> '; 

for (var page = 1; page <= this.pages; page++) 

pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerName + '.showPage(' + page + ');">' + 

page + '</span> '; 

pagerHtml += '<span onclick="'+pagerName+'.next();" class="pg-normal"> Next ?/span>'; 

element.innerHTML = pagerHtml; 

} 

} 

</script> 

Answer 1

我還沒有這樣做很長一段時間，但你可以用你這樣的腳本：

<script type="javascript"> 
    //<![CDATA[ 

    //Your JS Code 

    //]]> 
</script> 

這將停止W3C驗證器將JS解析爲標記。