0
您好我想添加表中的數據。然而，它並沒有出現在XAMPP（MySQL）中添加來自PHP的數據
我在做什麼錯了。花了很長時間看看有什麼不對，但我找不到任何東西。
fyi。
config.php連接PHPto MySQL。和 clean.php清理變量。
<?php
session_start();
echo "<div style='text-align:right'><h1>Welcome ". $_SESSION['SESS_FIRST_NAME']."!</h1> </div>";
if($_SESSION['SESS_admin'] == 0)
{
require("do_menu.php");
echo "<div style='text-align:right'>
<form action='SearchUser.php' method='POST'>
<Table border='0' align='right'>
<tr>
<td >
<select name='SEARCH' id='SEARCH'>
<option value='ID_NO' selected='selected'>ID Number</option>
<option value='FNAME'>First Name</option>
<option value='LNAME' >Last Name</option>
<option value='MNAME'>Middle Name</option>
<option value='DATE'>Birthday</option>
<option value='SEX'>SEX</option>
<option value='AGE'>Age</option>
<option value='STATUS'>Status</option>
<option value='TEL_NO'>Landline Number</option>
<option value='ADDRESS'>Address</option>
<option value='OCCUPATION'>Occupation</option>
<option value='REFERRED_BY '>Referrals</option>
<option value='itResult'>Result</option>
</select>
</td>
<td rowspan =2><input name='SUBMIT' type='SUBMIT' id='SUBMIT' value='Search!'></td>
</tr>
<tr>
<td><input name='INPUT' type='text' id='INPUT'></td>
</tr>
</table><br>
</FORM> </div>";
}
else
require("do_menu3.php");
require("clean.php");
require("config.php");
require("auth.php");
require("do_html_header.php");
do_html_header();
do_menu();
?>
<?php
if (!$_POST['SUBMIT']){
?>
<center>
<form action="<?php print $_SERVER['PHP_SELF']; ?>" method="POST" name=register>
<table width="400" border="0" cellspacing="1" cellpadding="0" align="center">
<tr>
<td bgcolor="yellow"><H1>Add Specialist</H1></td>
</tr>
<tr>
<td width="100">
<fieldset>
<label for="name">name:</label>
<input
type="text"
id="name"
name="name"
maxlength="100"
onkeyup="checkNameForLength(this);" />
</fieldset>
</td>
</tr>
<tr>
<td width="100">
<fieldset>
<label for="spec_username">Specialist's Username:</label>
<input
type="text"
id="spec_username"
name="spec_username"
maxlength="100"
onkeyup="checkNameForLength(this);" />
</fieldset>
</td>
</tr>
<tr>
<td width="100">
<fieldset>
<label for="spec_password">Specialist's Password:</label>
<input
type="text"
id="spec_password"
name="spec_password"
maxlength="28"
onkeyup="checkNameForLength(this);" />
</fieldset>
</td>
</tr>
<tr>
<td width="100">
<input type="hidden" name="online_check" id="online_check" size="50" value="Y">
</td>
</tr>
<tr>
<td width="100"><center><input name="SUBMIT" type="SUBMIT" id="SUBMIT" value="SUBMIT">
<input type="RESET" value="RESET"></form>
<form action="login-form.php"><input type="SUBMIT" name="Submit" value="Go Back!"/></center></form></td>
</tr>
</table>
<?php
}
else {
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Function to sanitize values received from the form. Prevents SQL injection
$name = clean($_POST['name']);
$spec_username = clean($_POST['spec_username']);
$spec_password = clean($_POST['spec_password']);
$online_check = clean($_POST['online_check']);
$_SESSION["spec_id"] = $spec_id;
$_SESSION["name"] = $name;
$_SESSION["spec_username"] = $spec_username;
$_SESSION["spec_password"] = $spec_password;
$_SESSION["online_check"] = $online_check;
//Input Validations
if($name == '') {
$errmsg_arr[] = 'Name missing';
$errflag = true;
}
if($spec_username == '') {
$errmsg_arr[] = 'Username missing';
$errflag = true;
}
if($spec_password == '') {
$errmsg_arr[] = 'Password missing';
$errflag = true;
}
if($online_check == '') {
$errmsg_arr[] = 'Online Check missing';
$errflag = true;
}
//If there are input validations, redirect back to the registration form
if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
print "You have input errors. These are:";
print "<BR><UL>";
for ($i=0; $i<sizeof($errmsg_arr); $i++) {
print "<LI>$errmsg_arr[$i]";
}
print "</UL>";
print "<A HREF=\"";
print $_SERVER['PHP_SELF'];
print "\">Go back</A>";
exit();
}
else {
echo "<center><BR><BR>You entered the following information:";
echo "<BR>Name = $name";
echo "<BR>Username = $spec_username";
echo "<BR>Password = $spec_password";
echo "<BR>Online Check = $online_check";
$result = mysql_query("select * from specialist_info where spec_id = '$spec_id'");
if(!(mysql_num_rows($result) == 0)) {
print "<BR>User number $spec_id is already assigned to another User<BR><A HREF =\"".$_SERVER['PHP_SELF']. "\">Go Back</A>";
@mysql_free_result($result);
exit();
}
$result = mysql_query("INSERT INTO specialist_info (spec_id, name, spec_username, spec_password, online_check) VALUES('$spec_id', '$name', '$spec_username',spec_password('$password'), '$online_check')");
print ("<BR><BR>1 record added");
}
}
?>
</BODY>
</HTML>
嚴重？請指出錯誤的位置 – 2011-03-29 22:57:55
我想放在數據庫中的數據沒有顯示在MySQL中。是的，它很嚴肅。 – 2011-03-29 23:14:06