將字符串轉換爲數組2D中的java

Question

我有這個字符串是查詢結果 07：40,09：00,10：20,11：40，| 08：00,09：00，|

1）我想消除最後一個|

2）如果你使用的是C將其轉換爲

String[][] matrix ={ 
    {"07:40","08:00"}, 
    {"09:00","09:00"}, 
    {"10:20",null}, 
    {"11:40",null} 
}; 

Answer 1

喜嘗試此解決方案它的工作原理，而不是隻在一個完美的方式，但它照顧空串和格式不正確的琴絃享受

   public static String[][] getModel(String answer){ 
    try { 
     System.out.println(answer); 
      if(answer.contains("|")){ 
          String[] cols=answer.split(",\\|"); 

          System.out.println("case found"); 
          System.out.println("size 1:"+cols.length); 

          int dimensionCol=cols.length; 
          int dimensionRow=cols[0].split(",").length; 

          System.out.println(dimensionCol+" "+dimensionRow); 
          String[][] result=new String[dimensionRow][dimensionCol]; 

          int i=0,j=0; 
          for(String colElement:cols){ 
           i=0; 
           String[] datas = colElement.split(","); 
           for (String data : datas) { 
            result[i][j]=(!data.equals(""))?data:null; 
            System.out.print(result[i][j]); 
            i++; 
           } 
           System.out.println(""); 
           j++; 
             } 
          return result; 
          }else{ 


            System.out.println("empty String return by null"); 
            return null; 


          } 
      }catch(Exception e){e.printStackTrace();} 
    return null; 
    } 

這裏是主要的測試方法

public static void main(String[] args) { 


    // String model = "07:40,09:00,10:20,11:40,|08:00,09:00,|"; 
    String model = ""; 
    String[][] model1 = getModel(model); 
      if (model1!=null) { 
     for (String[] model11 : model1) { 
       for (String model111 : model11) { 
        System.out.print(model111+" "); 
       } 
       System.out.println(""); 

    } 
    } 

} 

Answer 2

++，那麼你可以試試這個：

#include <bits/stdc++.h> 
using namespace std; 

vector<string>split(string str,string Separator) 
{ 
    vector<string>answer;string temp; 
    int len=str.size(); 
    for(int i=0;i<len;i++) 
    { 
     bool isSeparator=false; 
     for(int j=0;j<Separator.length();j++) 
      if(str[i]==Separator[j]) 
      isSeparator=true; 
     if(!isSeparator) 
     { 
      temp+=str[i];continue; 
     } 
     if(temp!="") 
      answer.push_back(temp);temp=""; 
    } 
    if(temp!="") 
     answer.push_back(temp); 
    return answer; 
} 
int main() 
{ 
    int i,j; 
    string str="07:40,09:00,10:20,11:40,|08:00,09:00,|"; 
    vector<string>v=split(str,"|"); // First split with respect to '|' 
    vector<string>matrix[100]; // Maximum row of time 
    for(i=0;i<v.size();i++) 
    { 
     vector<string>temp; 
     temp=split(v[i],","); // Now split with respect to ',' 
     for(j=0;j<temp.size();j++) 
     { 
      matrix[j].push_back(temp[j]); 
     } 
    } 
    for(i=0;;i++) 
    { 
     if(matrix[i].size()==0) // Break the loop, because no time will be on below 
      break; 
     for(j=0;j<matrix[i].size();j++) 
      cout<<matrix[i][j]<<" "; 
     cout<<"\n"; 
    } 
return 0; 
} 

Answer 3

我想：

1）elimitate最後 「|」使用例如substring()

2）分割字符串與string.split("|")，並保持長度爲numTimes

3）在所述分割結果週期和由substr.split(",")

4分割每個子串）保持的長度的最大長度在一個int的分割稱爲len

5）創建結果陣列String[][] matrix = new String[len][numTimes]

5）創建一個用於在循環中循環for (int i = 0; i < len; i++){...

6）添加正確的值到matrix（檢查null）

Answer 4

試試這個：

public static void main(String ars[]) { 
String string = "11:40,|08:00,09:00,|"; 
String[] str1 = string.split("\\|"); 
if (str1.length != 2) { 
    throw new IllegalArgumentException("I dont see a seperator | in your String"); 
} 
String[] rows = str1[0].split(","); 
String[] cols = str1[1].split(","); 
int maxLength = rows.length > cols.length ? rows.length : cols.length; 
String matrix[][] = new String[maxLength][2]; 

for (int row=0; row<rows.length; row++) { 
    matrix[row][0] = rows[row]; 
} 
for (int col=0; col<cols.length; col++) { 
    matrix[col][1] = cols[col]; 
} 

for (int i=0; i<maxLength; i++) { 
    System.out.println(Arrays.toString(matrix[i])); 
} 
}