bash中太多參數錯誤

Question

我正在編寫一個腳本來刪除目錄中的所有文件以供練習。我使用引號我的變量，但我仍然得到以下錯誤：

/usr/local/bin/deleteall: line 6: [: too many arguments 
/usr/local/bin/deleteall: line 11: [: too many arguments 

這裏是我的代碼：

#!/bin/bash 
#Deletes all files in the current directory 

read -p "You are about to delete all files in $(pwd). Are you sure you want to do this? y/n" yn 
echo $yn 
if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then 
     for i in `ls`; do 
       rm $i 
     done 
     exit; 
elif [ [ "$yn" = "n" ] -o [ "$yn" = "N" ] ] ; then 
     exit; 
else 
     read -p "Please enter y (yes) or n (no)" 
     exit; 
fi 

這是整個輸出：

You are about to delete all files in <my dir>. Are you sure you want to do this? y/nn 
n 
/usr/local/bin/deleteall: line 6: [: too many arguments 
/usr/local/bin/deleteall: line 11: [: too many arguments 
Please enter y (yes) or n (no)n 

我在做什麼錯？

Answer 1

此行似乎是問題：

if [ [ "$yn" = "y" ] -o [ "$yn" = "Y" ] ] ; then 

你可以取代這個：

if [[ "$yn" == [yY] ]]; then 

PS：做同樣的，你檢查n or N行。

Answer 2

這是你想要什麼：

read -p "Are you sure? " -n 1 -r 
echo # (optional) move to a new line 
if [[ $REPLY =~ ^[Yy]$ ]] 
then 
    for i in `ls`; do 
     rm -rf $i 
done 
fi 

if [[ $REPLY =~ ^[Nn]$ ]] 
then 
    #do what you want 
done 
fi 

Answer 3

不能嵌套[]。它將字面上的嵌套括號解釋爲參數，並打印出一個錯誤，這個錯誤太多了。

就在這個將採用雙支架和相同的邏輯

if [[ $yn == "y" || $yn == "Y" ]]; then 

而且工作

if [ "$yn" = "y" -o "$yn" = "Y" ]; then 

另一個替代語法

for i in `ls`; do 
    rm $i 
done 

真的應該

for i in *; do 
    [ -f "$i" ] && rm $i 
done 

因此，它只會嘗試刪除常規文件（除非您重寫了rm，並且您可以決定對符號鏈接執行什麼操作，否則您將得到dirs錯誤）。而ls只是無關緊要的。