登錄與HTTP POST網站

Question

我敢嘗試創建一個aplication本網站http://www.reclameaqui.com.br/ 登錄，當我把我的用戶名和密碼，該aplication告訴我這一點：

03-01 22： 34：47.220：W/SENCIDE（27717）：403禁止

禁止

您無權訪問此服務器上的/ areadoconsumidor /。

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Apache/2.2.15（CentOS）Server at www.reclameaqui.com.br Port 80 package com.sencide;

這是代碼

package com.sencide; 

import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.InputStreamReader; 
import java.util.ArrayList; 
import java.util.List; 

import org.apache.http.HttpResponse; 
import org.apache.http.NameValuePair; 
import org.apache.http.client.ClientProtocolException; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.entity.UrlEncodedFormEntity; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.apache.http.message.BasicNameValuePair; 

import android.app.Activity; 
import android.os.Bundle; 
import android.util.Log; 
import android.view.View; 
import android.view.View.OnClickListener; 
import android.widget.Button; 
import android.widget.EditText; 
import android.widget.TextView; 

public class AndroidLogin extends Activity implements OnClickListener { 

    Button ok,back,exit,site; 
    TextView result; 

    /** Called when the activity is first created. */ 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.main); 

    // Login button clicked 
     site = (Button)findViewById(R.id.button1); 
     site.setOnClickListener(this); 


     // Login button clicked 
     ok = (Button)findViewById(R.id.btn_login); 
     ok.setOnClickListener(this); 

     result = (TextView)findViewById(R.id.lbl_result); 

    } 

    public void postLoginData() { 
     // Create a new HttpClient and Post Header 
     HttpClient httpclient = new DefaultHttpClient(); 

     /* logar no site */ 
     HttpPost httppost = new HttpPost("http://www.reclameaqui.com.br/includes/autenticaUsuario.php"); 

     try { 
      // Add user name and password 
      EditText uname = (EditText)findViewById(R.id.txt_username); 
      String username = uname.getText().toString(); 

      EditText pword = (EditText)findViewById(R.id.txt_password); 
      String password = pword.getText().toString(); 

      List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(6); 
      nameValuePairs.add(new BasicNameValuePair("identificador", username)); 
      nameValuePairs.add(new BasicNameValuePair("senha", password)); 
      nameValuePairs.add(new BasicNameValuePair("urlRedir", "http://www.reclameaqui.com.br/areadoconsumidor/")); 
      nameValuePairs.add(new BasicNameValuePair("tipo", "cadastro")); 
      nameValuePairs.add(new BasicNameValuePair("x", "35")); 
      nameValuePairs.add(new BasicNameValuePair("y", "24")); 
      httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 

      // Execute HTTP Post Request 
      Log.w("SENCIDE", "Execute HTTP Post Request"); 
      HttpResponse response = httpclient.execute(httppost); 

      String str = inputStreamToString(response.getEntity().getContent()).toString(); 
      Log.w("SENCIDE", str); 

      if(str.toString().equalsIgnoreCase("true")) 
      { 
       Log.w("SENCIDE", "TRUE"); 
       result.setText("Login successful"); 
      }else 
      { 
       Log.w("SENCIDE", "FALSE"); 
       result.setText(str);     
      } 

     } catch (ClientProtocolException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
    } 

    private StringBuilder inputStreamToString(InputStream is) { 
     String line = ""; 
     StringBuilder total = new StringBuilder(); 
     // Wrap a BufferedReader around the InputStream 
     BufferedReader rd = new BufferedReader(new InputStreamReader(is)); 
     // Read response until the end 
     try { 
      while ((line = rd.readLine()) != null) { 
       total.append(line); 
      } 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
     // Return full string 
     return total; 
    } 

    @Override 
    public void onClick(View view) { 
     if(view == ok){ 
      postLoginData(); 
     } 
    } 

} 

什麼我可以做應用程序的偉大工程？誰來幫幫我;

Answer 1

它看起來像你張貼到錯誤的頁面。

<form action="includes/autenticaUsuario.php" method="post" onsubmit="return valida_form(this)">

形式出現張貼到http://www.reclameaqui.com.br/includes/autenticaUsuario.php。

它還隱藏字段：<input type="hidden" name="urlRedir" value="http://www.reclameaqui.com.br/areadoconsumidor/">

和

<input type="hidden" name="tipo" value="cadastro">

其次，用戶名輸入命名<input type="text" name="identificador">和密碼輸入被命名爲<input type="password" name="senha">，所以我相信你BasicNamveValuePairs應該更喜歡這個：new BasicNameValuePair("identificador", identificador)和new BasicNameValuePair("senha", senha)

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這也許應該是這個樣子：

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4); 
nameValuePairs.add(new BasicNameValuePair("tipo", "cadastro")); 
nameValuePairs.add(new BasicNameValuePair("urlRedir", "http://www.reclameaqui.com.br/areadoconsumidor/")); 
nameValuePairs.add(new BasicNameValuePair("identificador", identificador)); 
nameValuePairs.add(new BasicNameValuePair("senha", senha)); 

Answer 2

插入一箇中間HTTP代理服務器，或使用某種形式的HTTP調試的，這樣就可以比較後的網址，並從工作登錄張貼的所有數據與您的程序登錄。這將指出一些問題。