2017-07-12 86 views
0

我需要幫助,制定按自定義時間範圍(無間隔)分組的值的摘要,然後按天分組。例如:按DAYNAME分組的MySQL時間範圍

Monday (00:00-07:00, 07:00-11:00, 11:00-13:00, 13:00-19:00 and 19:00-00:00) 
Tuesday (00:00-07:00, 07:00-11:00, 11:00-13:00, 13:00-19:00 and 19:00-00:00) 
Wednesday (00:00-07:00 ... 

我知道按工作日將是:

select count(values), DAYNAME(date) as Day from data group by Day; 

並做了正常的非時間範圍爲:

select sum(case when clients between 0 and 30 then 1 end) as '0-30' 
,sum(case when clients between 30 and 120 then 1 end) as '30-120' 
,sum(case when clients between 120 and 300 then 1 end) as '120-300' 
,sum(case when clients between 300 and 900 then 1 end) as '300-900' 
,sum(case when clients between 900 and 1800 then 1 end) as '900-1800' 
,sum(case when clients between 1800 and 3600 then 1 end) as '1800-3600' 
,sum(case when clients between 3600 and 14400 then 1 end) as '3600-14400' 
,sum(case when clients >= 14400 then 1 end) as '14400+' 
    from data; 

但是怎麼辦呢時間範圍和平日?

+0

當然,如果您曾經給過它超過一週的數據,您的示例代碼將開始返回令人困惑的結果。 –

回答

0

沒關係。我自己找到了答案:

SELECT sum(value), date, DAYNAME(date) as Day, case 
when TIME(date) >= '00:00' and TIME(date)< '07:00' then '00:00-07:00' 
when TIME(date) >= '07:00' and TIME(date)< '11:00' then '07:00-11:00' 
when TIME(date) >= '11:00' and TIME(date)< '13:00' then '11:00-13:00' 
when TIME(date) >= '13:00' and TIME(date)< '19:00' then '13:00-19:00' 
else '19:00-00:00' 
end as time_period 
from data group by Day, time_period;