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這是我的代碼的過程,但它返回重複數我想來電號碼從通話記錄中,但沒有重複號,如果重複相同數量的
Cursor c = getApplicationContext().getContentResolver()
.query(CallLog.Calls.CONTENT_URI, null, CallLog.Calls.TYPE+" = ? ",
new String[]{String.valueOf(CallLog.Calls.INCOMING_TYPE)},
CallLog.Calls.DATE + " DESC");
ListView numListView = (ListView) findViewById(R.id.list);
CallCursorAdapter adapter = new CallCursorAdapter(this, c);
numListView.setAdapter(adapter);