（java）是否有可能從同一行中的用戶2值，一個字符串和另一個double讀取？

Question

這個程序的想法是不斷地從用戶那裏讀取一個產品名稱，它的價格在同一行中，直到用戶類型停止，然後計算用戶是否有足夠的資金。但我輸入兩條線後得到一個錯誤，這是我寫的（請大家幫忙）：

import java.util.Scanner; 
public class AA_152 { 
public static void main (String[] args){ 
Scanner input = new Scanner(System.in); 

System.out.print("How much money do you have? "); 
double money = input.nextDouble(); 

double price; 
double total = 0; 
String product; 
Scanner input1 = new Scanner(System.in); 
System.out.println("Please, Insert the items in the invoice (the name product 
and its price):\n" 
     + "Insert \"stop\" as the name product to finish your input "); 
while (!input1.next().equals("stop")){ 
product = input1.next(); 
price = input1.nextDouble(); 
total += price; 
} 
if (total <= money) 
System.out.println("you have enough money"); 
else 
    System.out.println("you don\'t have enough money"); 

}  
} 

這是我得到的錯誤，當我運行程序：

How much money do you have? 100 
Please, Insert the items in the invoice (the name product and its price): 
Insert "stop" as the name product to finish your input 
orange 12.200 
water 15.400 
Exception in thread "main" java.util.InputMismatchException 
    at java.util.Scanner.throwFor(Scanner.java:864) 
    at java.util.Scanner.next(Scanner.java:1485) 
    at java.util.Scanner.nextDouble(Scanner.java:2413) 
    at AlaaAwad_152306.main(AlaaAwad_152306.java:27) 
C:\Users\Alaa\AppData\Local\NetBeans\Cache\8.2\executor-snippets\run.xml:53: 
Java returned: 1 
BUILD FAILED (total time: 16 seconds) 

Answer 1

public static void main (String[] args){ 
     Scanner input = new Scanner(System.in); 
     // Q1 
     System.out.print("How much money do you have? "); 
     double money = Double.valueOf(input.nextLine()); 
     HashMap<String,Double> products = new HashMap<String,Double>(); 
     //Q2 
     double total = 0; 
     String[] product; 
     String line=""; 
     Scanner input1 = new Scanner(System.in); 
     System.out.println("Please,insert the items in the invoice (this typo : 'name-price'):\n" 
       + "Insert \"stop\" as the name product to finish your input "); 
     while (!(line = input1.nextLine()).equalsIgnoreCase("stop")){ 
      product = line.split("-"); 
      products.put(product[0], Double.valueOf(product[1])); 
      total += Double.valueOf(product[1]); 
      System.out.println("Another one ?"); 
     } 
     if (total <= money){ 
      System.out.println("you have enough money for "+products); 
     }else{ 
      System.out.println("you don\'t have enough money for "+products); 
     } 
     input1.close(); 
    }  

所以薩姆改進：

• 我添加一個HashMap來存儲對產品名稱/價格，HashMap的是存儲對
最便捷的方式
• 在while條件1分的事情是由：輸入存儲在line和檢查它是否是「停止」，因爲你的代碼，你需要2個輸入，每次需要一個線時間也各產品之間的寫入停止的不同
• 我建議你像'name - price'這樣問，那麼分離和保存就更容易了，因爲如果分隔符是一個你不能購買的空間，例如「apple pie」^^
• 並且在打印中添加了打印產品清單

如果您需要更多信息，請在評論中告訴我，例如可以在輸入處添加一個檢查以驗證錯誤名稱價格是驗證，然後找到最小/最大也很容易與地圖

//'Classic' method for min price without using complex notions 
double min = Double.MAX_VALUE; 
//iterate over the prices 
for(Double price : products.values()){ 
    min = Math.min(min, price); 
} 
System.out.println("min is "+min); 

//Second method with Stream (allow to iterate easliy) 
double minBis = products.values().stream().min(Comparator.naturalOrder()).get(); 
System.out.println("mins is "+minBis);