-3
因此，我正在應用程序，直到我得到一個錯誤，我不明白爲什麼這不起作用，本質上代碼試圖把東西放在數據庫中，這是不做。我得到了這個錯誤。一般錯誤：1366錯誤的整數值
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY000]: General error: 1366 Incorrect integer value: '' for column 'id' at row 1' in /Users/DannyTran/Desktop/WebServer/social-network/classes/DB.php:10 Stack trace: #0 /Users/DannyTran/Desktop/WebServer/social-network/classes/DB.php(10): PDOStatement->execute(Array) #1 /users/DannyTran/Desktop/WebServer/social-network/register.php(24): DB::query('INSERT INTO use...', Array) #2 {main} thrown in /Users/DannyTran/Desktop/WebServer/social-network/classes/DB.php on line 10
這裏是我將不得不代碼：
數據庫：
CREATE TABLE `users` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`username` varchar(255) NOT NULL DEFAULT '',
`first_name` varchar(255) NOT NULL DEFAULT '',
`last_name` varchar(255) NOT NULL DEFAULT '',
`email` varchar(255) NOT NULL DEFAULT '',
`password` varchar(255) NOT NULL DEFAULT '',
`gender` varchar(11) NOT NULL DEFAULT '',
`country` varchar(255) NOT NULL DEFAULT '',
`verified` int(11) NOT NULL,
`role` varchar(255) NOT NULL DEFAULT '',
`bio` text,
`website` text,
`status` text,
`register` date NOT NULL,
`last` date NOT NULL,
`activated` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Register.php：
<?php
include('./classes/DB.php');
$pdo = new PDO('mysql:host=127.0.0.1;DBname=socialnetwork;charset=utf8', 'root', 'password');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
if(isset($_POST['register'])) {
$fn = strip_tags(@$_POST['fname']);
$ln = strip_tags(@$_POST['lname']);
$un = strip_tags(@$_POST['uname']);
$em = strip_tags(@$_POST['email']);
$pswd = strip_tags(@$_POST['password']);
$pswd2 = strip_tags(@$_POST['password2']);
$country = strip_tags(@$_POST['country']);
$gender = strip_tags(@$_POST['gender']);
$date = date("m-d-Y"); // Year - Month - Day
$no = 0;
$role = 'Member';
$status = 'Hello world!';
$website = '';
$bio = '';
DB::query('INSERT INTO users VALUES (\'\' , :username, :first_name, :last_name, :email, :password, :gender, :country, :verified, :role, :bio, :website, :status, :register, :last, :activated)', array(':username'=>$un,':first_name'=>$fn, ':last_name'=>$ln, ':email'=>$em, ':password'=>$pswd, ':gender'=>$gender, ':country'=>$country, ':verified'=>0, ':role'=>$role, ':bio'=>$bio, ':website'=>$website, ':status'=>$status, ':register'=>$date, ':last'=>$date, ':activated'=>0));
echo "Welcome!";
};
?>
<h1>Register Now</h1>
<form action="#" method="post">
<input type="text" placeholder="First Name" name="fname" required/><br /><br />
<input type="text" placeholder="Last Name" name="lname" required/><br /><br />
<input type="text" placeholder="Username" name="uname" required/><br /><br />
<input type="email" placeholder="E-Mail Address" name="email" required/><br /><br />
<input type="password" placeholder="Password" name="pswd" required/><br /><br />
<input type="password" placeholder="Confirm Password" name="pswd2" required/><br /><br />
<select name="gender">
<option value="" disabled selected>Gender</option>
<option value="Male">Male</option>
<option value="Female">Female</option>
<option value="Other">Other</option>
</select><br /><br />
<?php require_once './options/countries.php'; ?><br /><br />
<input name="register" type="submit" value="Login" /><br /><br />
</form>
<a href="login.php">Have an account? Login!</a>
db.php中：
<?php
class DB {
private static function connect() {
$pdo = new PDO('mysql:host=127.0.0.1;dbname=socialnetwork;charset=utf8', 'root', 'password');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
return $pdo;
}
public static function query($query, $params = array()) {
$statement = self::connect()->prepare($query);
$statement->execute($params);
// $data = $statement->fetchAll();
// return $data;
}
}
?>
我WO我很感激我能得到的任何幫助，謝謝！
儘量不要有五行寬的代碼行。 –
這個問題與PHP無關。這是你的MySQL查詢的問題。請將您的問題縮小到未來的特定單一技術。 –
通常情況下，你試圖插入一個錯誤的類型值，關於列規範，例如'string'到'int'。我建議你首先縮進你的sql - 這樣做更具可讀性 - 然後逐個將值類型與列類型進行比較。 – butterFlyNick