開放JavaFX的窗口是相對路徑

Question

我需要從一個JavaFX CONTROLER

Stage graphStage = new Stage(); 
    FXMLLoader loader = new FXMLLoader(); 
    fenetre = new File("../graph/graph.fxml"); 
    if (!fenetre.exists()) { 
     System.out.println("fichier inexistant"); 
    } else { 
     Pane rootGraph = loader.load(getClass().getResource(fenetre.getPath()).openStream()); 
     GraphController controller = (GraphController) loader.getController(); 
     controller.getSystemChoice(id); 
     Scene sceneGraph = new Scene(rootGraph); 
     sceneGraph.getStylesheets().add(getClass().getResource("myStyle.css").toExternalForm()); 

     graphStage.setTitle("Graphe"); 
     graphStage.setScene(sceneGraph); 
     graphStage.show(); 
    } 

代碼不fincd文件，如何達到這個文件打開一個窗口FXML？

controler is on: cloud/composant/controler.java 
my fxml is on: cloud/graph/graph.fxml 

Answer 1

要麼從文件中獲取數據，要麼使用資源。

不要試圖將兩種方法結合起來。它們往往不相容。

// assuming here the file path is correct 
FXMLLoader loader = new FXMLLoader(fenetre.toURI().toURL()); 
... 
Pane rootGraph = loader.load(); 

如果該文件是一種資源，你應該更喜歡將其加載爲資源，但：

// assuming cloud is positioned in the "classpath root" 
FXMLLoader loader = new FXMLLoader(getClass().getResource("/cloud/graph/graph.fxml"));